All categories

3 years ago

What slope of the points (9,7) and (3,3)

Mathematics

2 answers:

Ymorist [56]3 years ago

8 0

Answer:

6/4

Step-by-step explanation:

Veronika [31]3 years ago

3 0

Answer:

slope

−

Explanation:

to calculate the slope m use the

gradient formula

∙

−

let

(

)

(

−

)

and

(

)

(

−

)

⇒

−

(

−

)

−

Step-by-step explanation:

You might be interested in

Find the equivalent expression using the same basses (61*31)^8

lisabon 2012 [21]

Answer:

52026353283901

Step-by-step explanation:

4 0

4 years ago

GE = 5x+36 and GF= 2x+51. What is the value of x?

Pepsi [2]

Answer:

Step-by-step explanation:

8 0

3 years ago

An unknown capital gets added 5% interest per year by a bank. After how many years does the capital get three times as big, cons

shepuryov [24]

Answer:

After 23 years , the capital will get three times as big

Step-by-step explanation:

Firstly, let us write the compound interest formula

P = I( 1 + r)^n

Since we are considering a capital rise of 3 times

If I, the initial value is x, the P

value later will be 3x

Interest rate is 5/100 = 0.05

so we need the value of t

This will be;

3x = x(1 + 0.05)^t

3= 1.05^t

ln 3 = t ln 1.05

t = ln 3/ln 1.05

t = 23 years

6 0

3 years ago

A taxi cab company charges two dollars plus $.80 for each mile if you have $10 how many miles can you travel what type of functi

Delicious77 [7]

Answer:

You can go 10 miles.

Step-by-step explanation:

10-2= 8

8/.8= 10

10 miles

5 0

3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago