2+20t-5t^2=12
5t^2-20t+10=0
t^2-4t+2=0 complete the square
t^2-4t=-2
t^2-4t+4=2
(t-2)^2=2
t-2=±
t=2±
t≈(0.586, 3.41)
5t^2-20t+10=0
t^2-4t+2=0 complete the square
t^2-4t=-2
t^2-4t+4=2
(t-2)^2=2
t-2=±
t=2±
t≈(0.586, 3.41)
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Answer:
Step-by-step explanation:
1). Equation of a line which has slope 'm' and y-intercept as 'b' is,
y = mx + b
If slope 'm' = 1 and y-intercept 'b' = -3
Equation of the line will be,
y = x - 3
x - y = 3
2). Equation of a line having slope 'm' and passing through a point (x', y') is,
y - y' = m(x - x')
If the slope 'm' = 1 and point is (-1, 2),
The the equation of the line will be,
y - 2 = 1(x + 1)
y = x + 1 + 2
y = x + 3
x - y = -3
3). Equation of a line passing through two points and
will be,
If this line passes through (-2, 3) and (-3, 4),
y - 3 = -1(x + 2)
y = -x - 2 + 3
y = -x + 1
x + y = 1