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3 years ago

The area of rectangular garden. 50m long is 450 sq.m. Find the width of the garden

Mathematics

1 answer:

san4es73 [151]3 years ago

3 0

Answer:

9 m

Step-by-step explanation:

A= l * w

A= 450 sq m

l= 50 m

450= 50 * w

w= 450/50

w= 9

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vladimir2022 [97]

Answer:

12i

Step-by-step explanation:

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3 0

3 years ago

Find the value of each variable. Write an<br> equation then solve showing ALL the work<br> A2x+10°

AveGali [126]

Answer:

x = 25

Step-by-step explanation:

The three straight lines in the sides of the triangle means that ALL 3 SIDES ARE EQUAL.

This is an equilateral triangle. So all 3 angles are equal.

We know sum of 3 angles in a triangle is 180. Since 3 of the angles are equal, each angle is:

180/3 = 60

The top angle is given as "2x + 10", thus we can say "2x + 10" is equal to 60 degrees. Now we equate and solve for x:

$2x+10=60\\2x=60-10\\2x=50\\x=\frac{50}{2}\\x=25$

The value of x is 25

4 0

3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

What is the slope of the line that passes through points (6, 7) and (4, 2)?

Maslowich

The slope is 2.5!

y=2.5x-8

Hope this helps!

8 0

3 years ago

-A library currently has 125 audiobooks. The library plans to

Agata [3.3K]

Answer: 1 the 2 of 3 and 5a 5 to 6 in 8 is 9 be 9 that 9 was 10 he 11 for 11 it 14 with 15 ... 42 him 43 been 44 has 44 more 45 if 45 no 47 out 48 do 49 so 50 can 50 what ... right 143 might 146 came 146 off 147 find 148 states 149 since 149 used ... 1383 circle 1383 ought 1384 garden 1386 library 1390 accuse 1390

Step-by-step explanation:

5 0

3 years ago