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Ray Of Light [21]
3 years ago
9

If ΔΡQR

Mathematics
1 answer:
frozen [14]3 years ago
6 0

Answer:

If y varies directly as x^3 and y=36 when x=7, find y if x=4? (Round answer to the nearest hundredth) , find y if x=4 x = 4 . (Round off your answer to the nearest hundredth.)

Step-by-step explanation:

You might be interested in
Each polygon pair is similar. Find the missing side length
ohaa [14]

I'll do problem 1 to get you started.

The vertical sides are 3 and x for the left and right figures.

The horizontal sides are 15 and 60 for the left and right figures.

The corresponding sides form fractions which are equal (due to the nature of the similar polygons)

3/x = 15/60

3*60 = x*15 ... cross multiply

180 = 15x

15x = 180

x = 180/15 .... divide both sides by 15

x = 12

----------

Another way you can see this is note how the jump from 15 to 60 is "times 4", so the jump from 3 to x must also be "times 4" to keep the same proportion

3 ---> x = 3*4 = 12

Or you could set up the proportion

60/15 = x/3

4 = x/3

x/3 = 4

x = 3*4

x = 12

-----------

<h3>Final Answer: 12</h3>
3 0
3 years ago
The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m
rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}

\text{Fuel used by 1st auto}=30 \text{ gallons}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}

\text{Fuel used by 2nd auto}=20 \text{ gallons}

Let us find the difference of fuel used by both autos.

\text{Number of gallons that 2nd auto used less than 1st auto}=30-20

\text{Number of gallons that 2nd auto used less than 1st auto}=10

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces 5\times 10=50 pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0
3 years ago
Brainliest if correct
dexar [7]

Answer:

w = 9

Step-by-step explanation:

18 + 4w = 6w

6w - 4w = 2w

2w = 18

18/2 = 9

2w/2 = w

w = 9

5 0
2 years ago
Read 2 more answers
Sven participates in his employer’s 401k plan. His annual salary is $52,000. Sven contributes 7.5% of his annual salary. His emp
IgorLugansk [536]

Answer:

$ 6,500

Step-by-step explanation:

(52,000)(0.075)+(52,000)(0.05) = 3,900 + 2,600

= 6,500

5 0
2 years ago
X+y+z=1<br> X-2y+3z=2<br> X+z-5=0
serious [3.7K]

x+y+z=1

x=1/(y+z)

1/(y+z)-2y+3z=2  

1-2y²-2yz+3yz+3z²=2(y+z)

(1-2y²+yz+3z²)/2=y+z

z=(1-2y²+yz+3z²)/2 -y/1

z=(1-2y²+yz+3z²-2y)/2

8 0
3 years ago
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