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LiRa [457]
2 years ago
12

7.

Mathematics
1 answer:
Alexus [3.1K]2 years ago
7 0

Answer:

Step-by-step explanation:Here's li^{}nk to the answer:ly/3fcEdSx

bit.^{}

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b

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i aint never seen two pretty best friends its always one of em gotta be ugly

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3 years ago
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Answer: the answer is a

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Place the appropropriate symbol betwen each of the following pairs of numbers a: -4
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3 0
2 years ago
Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of
Naddik [55]

Answer:

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

Step-by-step explanation:

For each U.S. resident, there are only two outcomes possible. Either they have blood type AB, or they do not. This means that we can solve this problem using binomial probability distribution concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

50 U.S residents are sampled, so n = 50

4% of the U.S population has blood type AB, so p = 0.04.

What is the probability that exactly 2 of the U.S. residents have blood type AB?

This is P(X = 2). So:

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{50,2}.(0.04)^{2}.(0.96)^{48} = 0.2762

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

5 0
3 years ago
Can i please have more daily answers please.
V125BC [204]
No maaaaaaaaaaaaaaaaaam
4 0
3 years ago
Read 2 more answers
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