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3 years ago

In a shipment of 500 light bulbs, 25 of them were broken. What percentage of the light bulbs were broken?

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

8 0

Yeah 5 percent would be correct

Oxana [17]3 years ago

3 0

Answer:

Step-by-step explanation:

25/500 = .05 move the decimal twice to the right for percentage = 5%

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BRAINLIEST AND POINTS!!! PLEASE EXPLAIN

timofeeve [1]

Answer:

Option C. $\$23,134.61$

Step-by-step explanation:

we know that

$A=\frac{P[(1+r)^{n} -1]}{r(1+r)^{n}}$

we have

$P=\$400$

$r=0.075/12=0.00625$

$n=6*12=72\ months$

substitute in the formula

$A=\frac{400[(1+0.00625)^{72} -1]}{0.00625(1+0.00625)^{72}}\\ \\A=\frac{226.446972}{0.009788}\\ \\A=\$23,134.61$

4 0

2 years ago

A circle has a diameter of 26 feet. Find its circumference and area.

iogann1982 [59]

Answer: 81.64 feet

Step-by-step explanation:

Circumference of a circle = pi * diameter

Circumference of a circle = 3.14 * 26 feet

Circumference of a circle = 81.64 feet

5 0

2 years ago

PLS HELP!! Given the diagram below, find the value of x. The value of x is

Paha777 [63]

Answer:

44°

Step-by-step explanation:

180-30-14=136

180-136

7 0

2 years ago

What is the factorization of the expression below 16x2 - 49?

mrs_skeptik [129]

$16 {x}^{2} - 49 \\ = {(4x)}^{2} - {7}^{2} \\ = (4x - 7)(4x + 7)$

7 0

2 years ago

Read 2 more answers

A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

Fynjy0 [20]

Answer:

The equation showing this situation is $D=b^2-4ac=0$

Step-by-step explanation:

Given : A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

To find : Which could be the equation?

Solution :

A quadratic equation in form $ax^2+bx+c=0$ has a solution $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ called a quadratic formula in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If $D=b^2-4ac>0$ there are two real roots.

2) If $D=b^2-4ac=0$ there are one real roots.

3) If $D=b^2-4ac$ there are no real roots.

According to question,

A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

So, The equation showing this situation is $D=b^2-4ac=0$

6 0

2 years ago