System of equations subtraction method
In the addition/subtraction method, the two equations in the system are added or subtracted to create a new equation with only one variable. ... Substitute the variable back into one of the equations and solve for the other variable. Check the solution--it should satisfy both equations.
<span>Here let the quadratic equation be ax^2 + bx + c
We know that a=5 from the question.
Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2).
However, let's assume that a2=1 and b2=6,
Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10
So, the equation is (5x-10)(x-6)</span>
Answer:
one to one function
Step-by-step explanation:
f(x)=6x+1 can only be a one to one function when x1=x2
Now,
f(x1)=f(x2)
or, 6x1 + 1 = 6x2 + 1
or, 6x1 = 6x2
or, x1 = x2
So f(x)= 6x + 1 is a one to one function
Answer:
-2x-6 I think
Step-by-step explanation:
I think that it is -2x-6 because I did -2 and x is -2x and -2 times -3 is 6.
