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s2008m [1.1K]
3 years ago
6

Write the quadratic equation whose roots are −6 and 2 , and whose leading coefficient is 5 . (use the letter x to represent the

variable.)
Mathematics
1 answer:
White raven [17]3 years ago
3 0
<span>Here let the quadratic equation be ax^2 + bx + c We know that a=5 from the question. Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2). However, let's assume that a2=1 and b2=6, Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10 So, the equation is (5x-10)(x-6)</span>
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Paha777 [63]

Answer:

\displaystyle y=\frac{4}{5}x+\frac{13}{5}

Step-by-step explanation:

The equation of the line in slope-intercept form is:

y=mx+b

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When two points are given, it's convenient to calculate the slope first.

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\displaystyle m=\frac{1-5}{-2-3}=\frac{4}{5}

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\displaystyle y=\frac{4}{5}x+b

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The required equation of the line is:

\boxed{\displaystyle y=\frac{4}{5}x+\frac{13}{5}}

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