Answer:
1) ABCD is a rhombus
2) All sides of a rhombus are equal.
4) SSS
5) CPCTC
Answer:
C or d
Step-by-step explanation:
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
(9+w)w=252 or w(w+9)=252.
The quadratic equation applies: w²+9w-252=0=(w+21)(w-12), so w=12, because a negative zero is meaningless.
So the dimensions are width=12 in and length=21 in.
Your question factored out would be 13mn^3 + 21p