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Dmitry_Shevchenko [17]
3 years ago
15

Find the area of the figure.

Mathematics
1 answer:
zmey [24]3 years ago
8 0

Answer:

the area of the figure is 16ft

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I need help with this plz
Alisiya [41]

Answer:Mmm

Step-by-step explanation:

I am doing the work I will thell you the answer

5 0
2 years ago
Please help and show steps so i could figure out how to do it , will give branliest!
erastova [34]

Answer:

8

Step-by-step explanation:

1. 3b - 2 (1 - b) / a - 2

2. 3(2) - 2 (1 - 2) / 3 - 2

3. 6 - 2 (-1) / 1

4. 6 + 2 / 1

5. 8 / 1

6. 8

3 0
2 years ago
How do you solve (3x+)(x+3), I dont want the answer, I just want to know how to solve it in complete sentences.
artcher [175]

Answer:

???????????//?///

Step-by-step explanation:

7 0
2 years ago
A manufacturing company wants to use a sample to estimate the proportion of defective tennis balls that are produced by a machin
Kitty [74]

Answer:

The least number of tennis balls needed for the sample is 1849.

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

 CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error for this interval is:

 MOE= z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

Assume that the proportion of all defective tennis balls is <em>p</em> = 0.50.

The information provided is:

MOE = 0.03  

Confidence level = 99%

<em>α</em> = 1%

Compute the critical value of <em>z</em> for <em>α</em> = 1% as follows:

 z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58

*Use a <em>z</em>-table.

Compute the sample size required as follows:

 MOE= z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

       n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}

          =[\frac{2.58\times \sqrt{0.50(1-0.50)} }{0.03}]^{2}\\\\=1849    

Thus, the least number of tennis balls needed for the sample is 1849.

8 0
3 years ago
Find the equation of the straight line that has slope m = -6 and passes through point (2, -7)
MAXImum [283]

Answer:

y

=

3

2

x

+

1

Explanation:

To find the slope  

(

m

)

of the straight line that passes through two points  

(

x

1

,

y

1

)

and  

(

x

2

,

y

2

)

apply:

(

y

1

−

y

2

)

=

m

(

x

1

−

x

2

)

In this example our two points are  

(

0

,

1

)

and  

(

2

,

4

)

Hence:  

(

1

−

4

)

=

m

(

0

−

2

)

−

3

=

−

2

m

→

m

=

3

2

The equation of a straight line in slope  

(

m

)

and intercept  

(

c

)

form is:

y

=

m

x

+

c

In this example:

y

=

3

2

x

+

c

Since the point  

(

0

,

1

)

is on this line  

→

1

=

0

+

c

Hence,  

c

=

1

∴

y

=

3

2

x

+

1

is our required straight line.

Step-by-step explanation:

3 0
3 years ago
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