Q7 Q17.) Find the magnitude, in kilograms, and the direction angle, in degrees, of the resultant force.
2 answers:
x-components = 1680sin40 + 1250sin60 = 2162.32kg
<span>y-components = 1680cos40 - 1250cos60 = 661.96kg</span>
<span>resultant force = | x-components + y-components | = 2261.37kg</span>
<span>direction is tan^-1(<span>2162.32/661.96) = N 73deg. W</span></span>
<span><span /></span>
Resultant force in W direction
=1680sin40deg + 1250sin60deg
=2162.415
resultant force in N direction
=1680cos40deg - 1250cos60deg
=661.955
magnitude of resultant force = sqrt(2162.315^2 + 661.955^2)
=2261.37
direction of resultant force = arctan(2162.315/661.955)
=73.0
You might be interested in
5/8x

15
The answer is C because x2 is a parabola
Add the numbers:
3-14x-x+25+15= 43-14-x
Combine like terms:
43-15x
Rearrange terms:
43-15x
-15x+43
Answer:
-15x+43
Hope this helps
I think It should be "Variable".

Let's solve for a :