Just did the test. It is not "Never". It is ALWAYS!!! If an equation has no solutions (like one with the same slope) THERE WILL BE NO SOLUTIONS!!!!!
Let p be: John goes to the beach
Let q be: He will go surfing.
Then in symbolic form, the argument becomes:

p ⇒ q
p
---------------------
∴ q
An argument is valid if the conjuction of the premises implies the conclusion.
p | q | p ⇒ q | (p ⇒ q) ∧ p | [(p ⇒ q) ∧ p] ⇒ q
---------------------------------------------------------------------\
F | F | T | F | T
F | T | T | F | T
T | F | F | F | T
T | T | T | T | T
The table above shows that the argument is a tautology.
Hence, the argument is valid
1) 0.095
2)0.1875
3)0.3
4)0.21875
5)0.133
6)0.66
7) 0.6
8)0.375
<span>First we calculate z using the formula:
z = (x - μ)/σ</span>
Where:
x = our variable, 10
μ = mean, 8
σ = standard dev, 2
Substituting known
values:<span>
z = (10 - 8)/2
z = 2/2
z = 1
Using the tables of
the normal distribution to find the p-value with z = 1
p = 0.8413
Since we want
"greater than 10”, we need to subtract the probability from 1
therefore
p* = 1 - 0.8413 = <span>0.1587</span></span>