Step 1: We make the assumption that 498 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=498$100%=498.
Step 4: In the same vein, $x\%=4$x%=4.
Step 5: This gives us a pair of simple equations:
$100\%=498(1)$100%=498(1).
$x\%=4(2)$x%=4(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{498}{4}$
100%
x%=
498
4
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{4}{498}$
x%
100%=
4
498
$\Rightarrow x=0.8\%$⇒x=0.8%
Therefore, $4$4 is $0.8\%$0.8% of $498$498.
Factoring, you have
h(t) = -16(t^2 -2 -8) = -16(t -4)(t +2)
The ball hits the ground when h(t) = 0, so
0 = -16(t -4)(t +2)
t = 4 or -2
The positive solution is the one of interest.
It will take 4 seconds for the ball to hit the ground.
Answer:
D Quadranr IV :)))))())))))))))))
8/1 x 2/3 = 16/3. 16/3 = 5 1/3