Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Answer:
answerrrrrrrr
Step-by-step explanation:
-4x^2+10x+4
I think D is the best option
A single die is consists of 6 sides. The sides consists of one to six dots. Therefore, tossing a single die will have 6 equal probabilities. That is, one to six dots.
(A) There are 3 numbers from 1 to 6 that are less than 4. Those are 1, 2, and 3. So, there are 3 possible outcomes. So, the probability of the event A happening is equal to 3/6 or 1/2.
(B) There are 2 numbers less than or equal to 2. Those are 1 and 2, itself. The probability of this event happening is 2/6 or 1/3.
(C) There are 3 numbers from 1 to 6 that are greater than 3. Those numbers are 4, 5, and 6. The probability of this event is equal to 3/6 or 1/2.
Answer:
The answer is -17
Step-by-step explanation:
All you have to do is multpily 5 and -4 then add 3
I will be happy if you give me brainlist