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nirvana33 [79]
3 years ago
5

The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.

Mathematics
1 answer:
notsponge [240]3 years ago
8 0

Answer:

-5 \to -24

-1 \to -4

2 \to 11

3 \to 16

4 \to 21

Step-by-step explanation:

Given

f(x) = 5x + 1

Required

Complete the table (see attachment)

When x = -5

f(-5) = 5 * -5 + 1 = -24

When x = -1

f(-1) = 5 * -1 + 1 = -4

When x = 2

f(2) = 5 * 2 + 1 = 11

When x = 3

f(3) = 5 * 3 + 1 = 16

When x = 4

f(4) = 5 * 4 + 1 = 21

So, the table is:

-5 \to -24

-1 \to -4

2 \to 11

3 \to 16

4 \to 21

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coldgirl [10]

Answer:

4 units

Step-by-step explanation:

3-2=1 unit

7-3=4 units

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7 0
4 years ago
Find all the zeros of the equation x^4-6x^2-7x-6=0
rusak2 [61]

Answer:

The zeros are

x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

a_0=6,\:\quad a_n=1

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}

-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2

=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\

=x^3-2x^2-2x-3

Again factor using the rational root test, we get

=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)

Using the zero product rule, we have

x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}

Therefore, the zeros are

x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}


4 0
3 years ago
Read 2 more answers
Please Help,
musickatia [10]
X=6 Z=8 so X:Z =. 6/8 So 2 goes into both 6 and 8 so divide numerator and denominator by 2 which = 3/4
4 0
4 years ago
Read 2 more answers
An education researcher claims that 58​% of college students work​ year-round. In a random sample of 400 college​ students, 232
Hatshy [7]

Answer:

The proportion of college students who work​ year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58​% of college students work​ year-round.

A random sample of 400 college​ students, 232 say they work​ year-round.

To test the researcher's claim use a one-proportion <em>z</em>-test.

The hypothesis can be defined as follows:

<em>H</em>₀: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> = 0.58.

<em>Hₐ</em>: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> ≠ 0.58. C

Compute the sample proportion as follows:

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The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

 p-value=2\times P(z

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work​ year-round is 58%.

6 0
4 years ago
(02.01)Polygon LMNP slides 5 units right and 4 units down on the coordinate plane. If the original measure of angle M was 50 deg
yarga [219]

Answer:

50°

Step-by-step explanation:

Transformation is the movement of one point from its initial location to a final location. If an object is transformed, all its points are transformed. Types of transformation is reflection, dilation, rotation and translation.

If an object is translated, it maintains its shape and size as well as the length of its sides and angles, only the location changes.

If polygon LMNP with ∠M of 50° is translated 5 units right and 4 units down to a new point, M' has the same angle measure. Hence ∠M' = 50°

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