Leanne runs a lap in 12 minutes. Kory runs a lap in 9 minutes. If they

Mathematics

1 answer:

klemol [59]4 years ago

6 0

Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .

<u>Step-by-step explanation:</u>

Here we have , Leanne runs a lap in 12 minutes. Kory runs a lap in 9 minutes. We need to find out that If they both start running at 10 am, at what time will they both cross the start together again . Let's find out:

Kory runs a lap in 9 minutes and , Leanne in 12 minutes , in order to find at what time will they both cross the start together again we will find LCM of 9 & 12 :

⇒ $\frac{9(4)}{12(4)}$

⇒ $\frac{36}{36}$

So ,LCM of 9 & 12 is 36 .That means Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .

In clear way , Kory will run race as :

1st lap = 9 minutes

2nd lap = 18 minutes

3rd lap = 27 minutes

4th lap = 36 minutes , i.e. at 10:36 am he'll complete his 4th lap

For , Leanne

1st lap = 12 minutes

2nd lap = 24 minutes

3rd lap = 36 minutes i.e. at 10:36 am he'll complete his 3rd lap .

This means Kory & Leanne will meet at 10:36 am completing there 4th and 3rd lap respectively .

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Answer:

a) The probability that all five are brand A is 0.0288

b) The probability that exactly two bottles are brand A is 0.0288

c) The probability that none of the bottles is brand A is 0.0048

Step-by-step explanation:

We have 9 bottles of brand A and 7 bottles of brand B.

The total of bottles is 16.

a) The probability that all five bottles are brand A is given by:

$P(5A)=\frac{9}{16} \frac{8}{15}\frac{7}{14} \frac{6}{13} \frac{5}{12}=\frac{3}{104}=0.0288$

b) Since we have 9 bottles of brand A we calculate the probability of picking two brand A bottles and the we calculate the probability of picking 3 brand B bottles:

$P(2A3B)=\frac{9}{16} \frac{8}{15}\frac{7}{14} \frac{6}{13} \frac{5}{12}=\frac{3}{104}=0.0288$