B) Factorise fully 8x + 12x

Plzzz help. Solve for x. Your answer must be simplified. 2x<15

tino4ka555 [31]

For all values of x less than 7.5 the above inequality satisfies , i.e $x$

Step-by-step explanation:

Inequalities are the relationships between two expressions which are not equal to one another. The symbols used for inequalities are <, >, ≤, ≥ and ≠.

$7 \textgreater x$ reads as '7 is greater than x' (or ' x is less than 7', reading from right to left).

$x \leq -4$ reads as ' x is less than or equal to -4' (or '-4 is greater than or equal to x', reading from right to left).

$x \neq 5$ reads as ‘ x is not equal to 5.

Here , we have

$\begin{aligned}&2 x$ { Dividing both sides by 2. }

∴ For all values of x less than 7.5 the above inequality satisfies.

5 0

3 years ago

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Drag each tile to the correct box.

ad-work [718]

Answer:

the first one first the second second and the last last

Step-by-step explanation:

2 1/5 + 22/5 = 4 2/5

9 2/5 + (-5 3/5)= 4 1/5

-8 2/5+9 1/5=1/15

8 0

3 years ago

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PLEASE HELP

Kamila [148]

Answer:

Step-by-step explanation:

5 0

3 years ago

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A bakery works out a demand function for its chocolate chip cookies and finds it to be q = D (x) = 943 - 17 x, where q is the q

Alex73 [517]

Answer:

See expla below

Step-by-step explanation:

Given the demand function:

q = D (x) = 943 - 17 x

a) Find the elasticity:

Find the derivative of the demand function.

D'(x)= -17

Thus, elasticity expression is:

$\frac{x D'(x)}{D'(x)}$

$= \frac{x (-17)}{943 - 17x}$

$= \frac{17x}{943 - 17x}$

Elasticity expression = $E(x) = \frac{17x}{943 - 17x}$

b) At what price is the elasticity of demand equal to 1?

This means E(x) = 1

Substitute 1 for E(x) in the elasticity equation:

$E(x) = \frac{17x}{943 - 17x}$

$1 = \frac{17x}{943 - 17x}$

Cross multiply:

$943 - 17x = 17x$

Collect like terms

$17x + 17x = 943$

$34x = 943$

$x = \frac{943}{34}$

x = 27.74

Elasticity at the price of demand = 1 is 27.74

c) At what prices is the elasticity of demand elastic?

This means E(x) > 1

Therefore,

$\frac{17x}{943 - 17x} > 1$

Cross multiply:

$17x > 943 - 17x$

Collect like terms

$17x + 17x > 943$

$34x > 943$

$x > \frac{943}{34}$

x > 27.74

The elasticity of demand is elastic at x > 27.74

d) At what prices is the elasticity of demand inelastic?

This means E(x) < 1

Therefore,

$\frac{17x}{943 - 17x} < 1$

Cross multiply:

$17x < 943 - 17x$

Collect like terms

$17x + 17x < 943$

$34x < 943$

$x < \frac{943}{34}$

x < 27.74

The elasticity of demand is inelastic at x < 27.74

e) At what price is the revenue a maximum:

Total revenue will be:

R(x) = x D(x)

= x (943 - 17x)

= 943x - 17x²

R(x) = 934 - 17x(price that maximizes total revenue)

Take R(x) = 0

Thus,

0 = 943 - 17x

17x = 943x

$x = \frac{943}{17}$

$x = 27.74$

Total revenue is maximun at x= 27.74 per cookie

f) At x = 21 per cookie, find the price:

Thus,

R (21) = (943 * 21) - (17 * 21²)

= 19803 - 7497

= 12306

At x = 27.74, find the price:

R(27.74) = (943 * 27.74) - (17 - 27.74²)

= 26158.82 - 13081.63

= 13077.19

We can see the new price of cookie causes the total revenue to decrease.

Therefore, with a small increase in price the total revenue will decrease.

5 0

3 years ago

Is 0.71428571428 a rational number

Alex787 [66]

No, since it a repeating(terminating) decimal, so it is not a rational number.

5 0

3 years ago

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