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Nuetrik [128]
3 years ago
10

Find the length of side x in the simplest radical form with a rational denominator

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

The value of x = 1

Step-by-step explanation:

Given

  • hypotenuse = √2
  • angle Ф = 45°

To determine

x = ?

Using the trigonometric ratio

cos Ф = adjacent / hypotenuse

here

Ф = 45°

adjacent of 45° = x

hypotenuse = √2

so substituting Ф = 45°  adjacent = x and hypotenuse = √2  in the equation

cos Ф = adjacent / hypotenuse

\cos \left(45^{\circ \:}\right)=\frac{x}{\sqrt{2}}

switch sides

\frac{x}{\sqrt{2}}=\cos \left(45^{\circ \:}\right)

Multiply both sides by 2

\frac{2x}{\sqrt{2}}=2\cos \left(45^{\circ \:}\right)

\sqrt{2}x=\sqrt{2}             ∵  \cos \left(45^{\circ \:}\right)=\frac{\sqrt{2}}{2}

Divide both sides by √2

\frac{\sqrt{2}x}{\sqrt{2}}=\frac{\sqrt{2}}{\sqrt{2}}

x=1

Therefore, the value of x = 1

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George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

  • The cost of small box of oranges = x
  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

3x + 14y = 203  ---------(1)

11x + 11y = 220  ---------(2)

<u>To solve these equations for x and y values :</u>

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- <u>(33x + 33y = 660)  </u>

  <u>        121 y = 1573  </u>

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

7 0
3 years ago
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JulijaS [17]
The answer is what that guys said





(Also what grade is this?)
4 0
3 years ago
The diameter of a circle is 16 meters. What is the angle measure of an arc bounding a sector with an area eight pi square meters
Degger [83]

Answer: 45°

Step-by-step explanation:

Diameter= 16m

Radius= 16/2 = 8m

The area of the circle= πr^2

= π8^2

= 64π square metres.

An area of 8π square metres is also 1/8 of the total area, therefore the arc must be 1/8 of the circumference.

The circumference = 2πr = 16π,

This gives us an arc length of 2π metres.

But since we are looking for the the angle.

In degrees: 360/8 = 45°

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3 years ago
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Answer:

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Step-by-step explanation:

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