Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d
Free_Kalibri [48]
The intersection of sets R and D is give by the following set:
R ∩ D = {3, 9, 15}.
<h3>What is the missing information?</h3>
This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.
<h3>What is the set that is the intersection of two sets?</h3>
The set that is the intersection of two sets is composed by the elements that belong to both sets.
For this problem, the sets are given as follows:
- R = {1,3,5,7,9,11,13,15,17}.
- D={3,6,9,12,15,18,21,24,27}
Hence the intersection is given by:
R ∩ D = {3, 9, 15}.
As the elements 3, 9 and 15 are the only ones that belong to both sets.
More can be learned about intersection of sets at brainly.com/question/11439924
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Answer:
1.5 years
Step-by-step explanation:
She will give up making $28,000 per year for 2 years. This means that she will give up making $56,000 in total.
$28,000 × 2 = $56,000
She also pay $34,000 in total to costs to get her degree. She invested a total of $90,000.
$56,000 + $34,000 = $90,000
After graduating, she makes $60,000 a year. It will take her 1.5 years to recover her investment.
90,000/60,000 = 1.5
Get x all alone on its own side:
x=16+5
x=21
Find <span>tan<span>(<span><span>5π</span>12</span>)</span></span> and sin ((5pi)/12)
Answer: <span>±<span>(2±<span>√3</span>)</span>and±<span><span>√<span>2+<span>√3</span></span></span>2</span></span>
Explanation:
Call tan ((5pi/12) = t.
Use trig identity: <span><span>tan2</span>a=<span><span>2<span>tana</span></span><span>1−<span><span>tan2</span>a</span></span></span></span>
<span><span>tan<span>(<span><span>10π</span>12</span>)</span></span>=<span>tan<span>(<span><span>5π</span>6</span>)</span></span>=−<span>1<span>√3</span></span>=<span><span>2t</span><span>1−<span>t2</span></span></span></span>
<span><span>t2</span>−2<span>√3</span>t−1=0</span>
<span>D=<span>d2</span>=<span>b2</span>−4ac=12+4=16</span>--> <span>d=±4</span>
<span>t=<span>tan<span>(<span><span>5π</span>12</span>)</span></span>=<span><span>2<span>√3</span></span>2</span>±<span>42</span>=2±<span>√3</span></span>
Call <span><span>sin<span>(<span><span>5π</span>12</span>)</span></span>=<span>siny</span></span>
Use trig identity: <span><span>cos2</span>a=1−2<span><span>sin2</span>a</span></span>
<span><span>cos<span>(<span><span>10π</span>12</span>)</span></span>=<span>cos<span>(<span><span>5π</span>6</span>)</span></span>=<span><span>−<span>√3</span></span>2</span>=1−2<span><span>sin2</span>y</span></span>
<span><span><span>sin2</span>y</span>=<span><span>2+<span>√3</span></span>4</span></span>
<span><span>siny</span>=<span>sin<span>(<span><span>5π</span>12</span>)</span></span>=±<span><span><span>√<span>2+<span>√3</span></span></span>2</span></span></span>
Answer:
The correct equation is "y=30x+6147". A further explanation is given below.
Step-by-step explanation:
The given values are:
(x1, y1) = (50, 7647)
(x2, y2) = (100, 9147)
As we know,
The slope is,
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
⇒ 
Now,
⇒ 
On substituting the given values in the above equation, we get
⇒ 
⇒ 
On adding "7647" both sides, we get
⇒ 
⇒ 