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solniwko [45]
3 years ago
6

A solution of sucrose in water has a boiling point that is _____ 100°C.

Chemistry
2 answers:
scoray [572]3 years ago
7 0
A solution of sucrose in water has a boiling point that is HIGHER THAN 100 DEGREE CELCIUS. Impurities in water usually raise the boiling point of water making the water to boil at an higher temperature than 100 degree Celsius. The raise in the boiling point of water depends on the concentration of sucrose that is added to the water. 
EastWind [94]3 years ago
6 0

Answer:

greater than

Explanation:

just took it and yes i know someone already answered but i figred this would be quicker!!!!!!

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4 years ago
For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this
Salsk061 [2.6K]

The following are the steps  to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3                           N = +5                        

O = -2                            O = -2

Ag = +1                         Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

     NO2– -----> NO3–

     Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

     NO2– + H2O -----> NO3–

     Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

    NO2– + H2O -----> NO3– + 2H+

     Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     2 Ag+ + 2e------> 2 Ag(s)

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3 years ago
The Lewis dot diagram for LiBr
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The chemical combination of the Atoms of two or more elements is known as a/an
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3 0
4 years ago
The standard free-energy change for this reaction in the direction written is 23.8 kJ/mol. The concentrationsof the three interm
Natali [406]

Answer: The actual free-energy change for the reaction  -8.64 kJ/mol.

Explanation:

The given reaction is as follows.

  Fructose 1,6-bisphosphate \rightleftharpoons Glyceraldehyde 3-phosphate + DHAP

For the given reaction, \Delta G^{o} is 23.8 kJ/mol.

As we know that,

       \Delta G = \Delta G^{o} + RT ln Q

Here,    R = 8.314 J/mol K,       T = 37^{o} C

                                                    = (37 + 273) K

                                                    = 310.15 K

Fructose 1,6-bisphosphate = 1.4 \times 10^{-5} M

Glyceraldehyde 3-phosphate = 3 \times 10^{-6} M

DHAP = 1.6 \times 10^{-5} M

Expression for reaction quotient of this reaction is as follows.

    Reaction quotient = \frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}

        Q = \frac{1.6 \times 10^{-5} \times 3 \times 10^{-6}}{1.4 \times 10^{-5}}

            = 3.428 \times 10^{-6}

Now, we will calculate the value of \Delta G as follows.

          \Delta G = \Delta G^{o} + RT ln Q

                      = 23800 + 8.314 \times 310.15 \times ln(3.428 \times 10^{-6})

                      = -8647.73 J/mol

                      = -8.64 kJ/mol

Thus, we can conclude that the actual free-energy change for the reaction  -8.64 kJ/mol.

7 0
3 years ago
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