The value of ΔG° (gibbs free energy change) is -2703kj and -2657kj.
Given ,
combustion reaction of butane :
C4H10(g) + 13/2O2 (g) →4CO2(g) + 5H2O(g)
Method-1 :
We know ,
ΔGrxn = sum of ΔG (product ) - sum of ΔG (reactant )
= [4 × (-394.4) + 5×(-228.6) ] - [1×(-16.7)]
ΔGrxn = -2720.6kj
Method-2 :
We know ,
ΔG = ΔH -TΔS
T =298K
Thus , ΔHrxn = sum of ΔH (product ) - sum of ΔH (reactant )
= [4×(-393.5) + 5×(-241.8) ] - [ 1×(-126)]
ΔHrxn = -2657kj
ΔSrxn = sum of ΔS (product ) - sum of ΔS( reactant )
= [ 4×(213.7) + 5×188.7 ] - [ 13/2 ×205 + 1×310 ]
ΔSrxn = 155.8j/K
ΔSrxn = 0.1558kj/K
Thus , ΔG = ΔH - TΔS
= -2657 - ( 298 × 0.1558kj/K )
ΔG = -2720kj
Hence , the value of ΔG is -2703kj .
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