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iren2701 [21]
3 years ago
15

When a sample of rust was mixed with acid, the rust changed into two simpler substances: W and Z. The substances W and Z could n

ot be broken down into simpler substances. Which statement is best supported by this evidence? A. The substances W and Z are compounds. B. Rust is a compound made of two elements. C. Rust is an element that breaks into compounds. D. The substances W and Z are not made of atoms.
Chemistry
2 answers:
julia-pushkina [17]3 years ago
6 0

here can be a number of chemical processes by which a compounds can be broken down into simpler substances. The most common and wide-spread of such processes is Catabolism. Along with anabolism, catabolism make up the metabolism process for living organisms. In catabolism, complex chemical molecules (such as proteins, polysaccharides, etc.) are broken down into simpler molecules (such as amino acids, monosaccharides, etc.). This is often accompanied by release of energy in the form of ATP (adenosine triphosphate) molecules and intermediate metabolites (which can be used by the organism in the anabolic processes). The energy thus generated is used for operation and maintenance of cells (and consequently, the body).  

Other processes that break down chemical substances into simpler substances, include depolymerization, decomposition, etc.

Hope this helps.

Arisa [49]3 years ago
6 0

The answer is B. Rust is a Compound made of two elements

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2a) Name two elements Found in waler.
OverLord2011 [107]

Answer:

Hydrogen and Oxygen

Pureified water has been filtered or processed to remove impurities like chemicals and other contaminants, while tap water is not and it is composed of minerals that may not be seen in purified water.

Chemicals are the most common type of water contaminants. They affect both surface and underground water bodies. Industries and farming activities are the leading cause.

Alcohol: Probable human mrcinogen

Arsenic: Skin hyperpigmentalion: oxidative stress;

peripheral neuropathy; bladden skin,

liver, lung, and lymphatic cancer

6 0
3 years ago
How many grams of ammonia (NH3) can be produced when 25 g of nitrogen gas reacts with 28 grams of hydrogen gas
Elis [28]

Answer:

34 g of NH₃

Explanation:

7 0
3 years ago
In what ways are the two designs in part C different? How do you think these differences will relate to the ability of each desi
Ilya [14]
The top one is different from the bottom because of is curvature shape while the bottom one is a square shape i think the bottom will heat up faster because of the nice even area inside where heat waves can evenly flow
4 0
3 years ago
At 2000 ∘C the equilibrium constant for the reaction 2NO(g)⇌N2(g)+O2(g) is Kc=2.4×103. If the initial concentration of NO is 0.1
Rasek [7]

Answer:

[N_2]=0.0866M

Explanation:

Hello there!

In this case, in agreement to the chemical reaction, it is possible for us to figure out the equilibrium concentration of the N2 product, via an ICE table plugged in the equilibrium expression:

Kc=\frac{[N_2][O_2]}{[NO]^2}\\\\2.4x10^3=\frac{x*x}{(0.175-2x)^2}

In such a way, when solving for x via quadratic equation or just a solver, it is possible to obtain:

x_1=0.0866M\\\\x_2=0.0884M

In such a way, since the root 0.0884 M produce a negative concentration of NO (0.175-2*0.0884=-0.0018M), we infer that the correct root is 0.0866 M; therefore, the concentration of N2 at equilibrium is equal to x:

[N_2]=x=0.0866M

Best regards!

4 0
3 years ago
A compound is 12.7% Al, 19.7% N, and 67.6% O. Determine its emperical formula.
gizmo_the_mogwai [7]

Answer:

AlN₃O₉

Explanation:

Assume that you have 100 g of the compound.

Then you have 12.7 g Al, 19.7 g N, and 67.6 g O.

1. Calculate the <em>moles</em> of each atom

Moles of Al = 12.7 × 1/26.98 = 0.4707 mol Al

Moles of N = 19.7 × 1/14.01    =  1.406   mol N

Moles of O = 67.6 × 1/16.00  = 4.225   mol O

2. Calculate the <em>molar ratios</em>.

Al: 0.4707/0.4707 = 1

N: 1.406/0.4707    = 2.987

O: 4.225/0.4707   = 8.976

3. Determine the <em>empirical formula</em>

Round off all numbers to the closest integer.

Al: 1

N: 3

O: 9

The empirical formula is AlN₃O₉.

3 0
4 years ago
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