Answer:
Hydrogen and Oxygen
Pureified water has been filtered or processed to remove impurities like chemicals and other contaminants, while tap water is not and it is composed of minerals that may not be seen in purified water.
Chemicals are the most common type of water contaminants. They affect both surface and underground water bodies. Industries and farming activities are the leading cause.
Alcohol: Probable human mrcinogen
Arsenic: Skin hyperpigmentalion: oxidative stress;
peripheral neuropathy; bladden skin,
liver, lung, and lymphatic cancer
The top one is different from the bottom because of is curvature shape while the bottom one is a square shape i think the bottom will heat up faster because of the nice even area inside where heat waves can evenly flow
Answer:
![[N_2]=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3D0.0866M)
Explanation:
Hello there!
In this case, in agreement to the chemical reaction, it is possible for us to figure out the equilibrium concentration of the N2 product, via an ICE table plugged in the equilibrium expression:
![Kc=\frac{[N_2][O_2]}{[NO]^2}\\\\2.4x10^3=\frac{x*x}{(0.175-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BN_2%5D%5BO_2%5D%7D%7B%5BNO%5D%5E2%7D%5C%5C%5C%5C2.4x10%5E3%3D%5Cfrac%7Bx%2Ax%7D%7B%280.175-2x%29%5E2%7D)
In such a way, when solving for x via quadratic equation or just a solver, it is possible to obtain:

In such a way, since the root 0.0884 M produce a negative concentration of NO (0.175-2*0.0884=-0.0018M), we infer that the correct root is 0.0866 M; therefore, the concentration of N2 at equilibrium is equal to x:
![[N_2]=x=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3Dx%3D0.0866M)
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Answer:
AlN₃O₉
Explanation:
Assume that you have 100 g of the compound.
Then you have 12.7 g Al, 19.7 g N, and 67.6 g O.
1. Calculate the <em>moles</em> of each atom
Moles of Al = 12.7 × 1/26.98 = 0.4707 mol Al
Moles of N = 19.7 × 1/14.01 = 1.406 mol N
Moles of O = 67.6 × 1/16.00 = 4.225 mol O
2. Calculate the <em>molar ratios</em>.
Al: 0.4707/0.4707 = 1
N: 1.406/0.4707 = 2.987
O: 4.225/0.4707 = 8.976
3. Determine the <em>empirical formula</em>
Round off all numbers to the closest integer.
Al: 1
N: 3
O: 9
The empirical formula is AlN₃O₉.