Question

Two triangles have the same area. One triangle has a base of 4 cm and a height of 7 cm. If the height of the other triangle is 14 cm, then what is its base length?
3 cm
2 cm
4 cm
5 cm​

Answer 1

Answer:

x = 2

Step-by-step explanation:

→ Work out the area of the first triangle

0.5 × 4 × 7 = 14

→ Set up an equation for the second base

0.5 × x × 14 = 14

→ Simplify

7x = 14

→ Divide both sides by 7

x = 2

Answer 2

Answer:

option B = 2cm

Step-by-step explanation:

$Area \ of \ first \ triangle = \frac{1}{2} \times base_1 \times height_1 \ [ \where base_1 = 4\cm \ height_1 \ = 7cm \ ]$

                                 $=\frac{1}{2} \times 4 \times 7 \\\\= 14 \ cm^2$

Given area of second triangle is same as first.

$Area \ of \ second \ triangle = \frac{1}{2} \times base_2 \times height_2 \ [ \ where \ height _ 2 = 14cm \ ]$

                           $14 = \frac{1}{2} \times base_2 \times 14\\\\14 = 7 \times base_2\\\\base_2 = 2 \ cm$