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Tatiana [17]
3 years ago
8

C - 3/4 = 1/8 Please answer

Mathematics
2 answers:
finlep [7]3 years ago
7 0

Answer:

The answer is 7/8.

Step-by-step explanation:

to get the answer you must use inverse operation so 3/4 + 1/8 = 0.875 or 7/8.

If this helped I would appreciate it if you marked me Brainliest. thank you and have a nice day!

Ymorist [56]3 years ago
4 0

Answer:

c = 7/8

Step-by-step explanation:

c - 3/4 = 1/8

First I will make sure that they all have the same denominator.

\frac{3}{4} * 2= \frac{6}{8}

Our new equation will look like:

c - 6/8 = 1/8

Now we will add 6/8 to both sides.

c = 1/8 + 6/8

c = 7/8

Our final answer is:

c = 7/8

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if you flipped one of the figures you will see that they are both the same shape and the same distance from the x and y axes.

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King sporting good have tow bikes on sale. One costs $89.98 and another costs $99.99 . What is the difference in the price of th
krok68 [10]

Answer:$ 10.01 would be the difference

Step-by-step explanation:

99.99

- 89.98

-------------

10.01

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PLZZ help me with this I really need your help
Georgia [21]
Basil yum just use ur brain and find out before asking for help, ask ur teacher or somthin
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Harlamova29_29 [7]

Answer: 9 = 6t

how many t's are there in the model? there are 6 ts. 6t makes 9, so 9 is equal to 6t.

ps. the equation could also be 6t = 9 but its basically the same thing (:

7 0
3 years ago
Check answer please
Cerrena [4.2K]
The fourth or the D) Option is correct.

To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.

Multiply the scalar quantity with each element with respect to its row and column positioning that is,

Row × Column. So;

(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.

To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.

\mathcal{A = \begin{bmatrix}1 & 0 & 3 \\ 2 & -1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad 7A = 7 \times \begin{bmatrix}1 & 0 & 3 \\ 2 & - 1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad \begin{bmatrix}7 \times 1 & 7 \times 0 & 7 \times 3 \\ 7 \times 2 & 7 \times -1 & 7 \times 2 \\ 7 \times 0 & 7 \times 2 & 7 \times 1 \\ \end{bmatrix}}

\therefore \quad \begin{\bmatrix}7 & 14 & 0 \\ 0 & -7 & 14 \\ 21 & 14 & 7 \end{bmatrix}

Hope it helps.
5 0
3 years ago
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