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3 years ago

12

Find the percent increase in the price per cheese stick.

1 answer:

BaLLatris [955]3 years ago

3 0

Take the price of the cheese stick then divide that by the old price. you will get a decimal. New divided by old. You should have some decimal that is 1.something. If its a percent increase of 64 percent you'd have 1.64 as the decimal. good luck.

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1<br> What is the equation of the line parallel to 8x - 16y= -14 and passing through (3, 0)?

andreev551 [17]

Answer:

8x -16y = 24

Step-by-step explanation:

8x - 16y= -14

A parallel line (i.e. same slope) will be: 8x - 16y= c

We have to find the value of "c".

If it passes through (x, y) = (3, 0) ⇒ 24 - 0 = c,

so equation is 8x -16y = 24

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3 years ago

What is the greatest common factor of 44c^5, 22c^3 and 11c^4

Alexxandr [17]

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of $44c^5, 22c^3 , 11c^4$

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

$\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}$

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

$\text{ Step 2: GCF of }c^5, c^3 , c^4$

$c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1$

Thus the greatest common factor is $c^3$

Step 3: Multiply the GCF of 44, 22, 11 and GCF of $c^5, c^3 , c^4$

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3$

Thus $\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

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3 years ago

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barxatty [35]

The answer is A hope this helps

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iragen [17]

Answer:

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Step-by-step explanation:

<u>Given Data:</u>

Speed = 4.9 mph

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<u>Required:</u>

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<u>Formula:</u>

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$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

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