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2 years ago

WILL GIVE BRANLIEST! pls help thank u sm!! :-) u are all amazing

Mathematics

2 answers:

34kurt2 years ago

7 0

Answer:

A.)

Step-by-step explanation:

A.)

irina1246 [14]2 years ago

6 0

Answer:

A :)

Step-by-step explanation:

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A rectangle measures 15 cm by 4 cm what's it's area

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The way you find area is multiplying width times height, so you have to multiply 15 by 4 which equals 60. Therefore the answer is 60

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Simplify 9 to the 2nd over 9 to the 7th

Allisa [31]

3387⁄200000000 or 0.00001693508

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2 years ago

A reflecting pool is shaped like a right triangle with one leg along the wall of a building. the hypotenuse is 9 feet longer tha

morpeh [17]

Answer:

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

Step-by-step explanation:

In the question, the shape of the pool is right triangle.

Let the leg side along the wall to be the x ft

Let the other leg side to be 7+x ft

Let the longest side/hypotenuse to be x+9 ft

Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse

This means;

$x^2 +(x+7)^2=(x+9)^2\\\\$

Expand the terms in brackets

$x^2+(x+7)^2=(x+9)^2\\\\\\x^2+x^2+14x+49=x^2+18x+81$

collect like terms

$x^2+x^2-x^2=18x-14x+81-49\\\\\\x^2=4x+32\\\\\\x^2-4x-32=0$

solve for x in the quadratic equation by factorization

$x^2-4x-32=0\\\\\\x^2-8x+4x-32=0\\\\\\x(x-8)+4(x-8)=0\\\\\\(x+4)(x-8)=0\\\\\\x+4=0,x=-4\\\\x-8=0,x=8$

Taking the positive value of x;

x=8ft

Finding the lengths

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

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3 years ago

59-(2c+3)=4(c+7)+c.

alisha [4.7K]

Step-by-step explanation:

${:}\leadsto$ $\sf 59-(2c+3)=4 (c+7)+c$

${:}\leadsto$ $\sf 59-2c-3=4c+28+c$

${:}\leadsto$ $\sf 56-2c=5c+28$

${:}\leadsto$ $\sf 5c+28=56-2c$

${:}\leadsto$ $\sf 5c+2c=56-28$

${:}\leadsto$ $\sf 7c=28$

${:}\leadsto$ $\sf c={\dfrac {28}{7}}$

${:}\leadsto$ $\sf c=4$

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2 years ago

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7nadin3 [17]

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