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3 years ago

Can you help me i dont know thw anwser

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

$\text{Let the side of square 1, square 2 and square 3 be x, y and z respectively.}\\\\\text{Given that,}\\\\\text{Perimeter of square 1,~~ p =100 units.}\\\\\text{So}~ x=\dfrac p 4 = \dfrac{100}4 =25~\text{units.}\\\\\\\text{Area of square 2, a = 225 units}^2\\\\\text{So}~y = \sqrt{a} = \sqrt {225} = 15~ \text{units.}\\\\\text{Use Pythagorean theorem to find z}^2\\\\x^2 =y^2 +z^2 \\\\\implies 25^2 = 15^2 +z^2\\\\\implies z^2 = 625 - 225 = 400\\\\\\$

$\text{Hence the area of square 3 is 400 units}^2.$

Verdich [7]3 years ago

6 0

Answer:

400 square units

Step-by-step explanation:

The side length of square 1 is 1/4 of its perimeter, so is 100/4 = 25 units. The area of square 1 is the square of the side length, so is 25² = 625 square units.

The area of square 3 is the difference in the areas of squares 1 and 2. This is due to the Pythagorean theorem.

area 3 = area 1 - area 2

area 3 = 625 -225

area 3 = 400 . . . . square units

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