M(dextrose) = 50 g.
V(solution) = 1 L.
n(dextrose) = 50 g ÷ 180 g/mol.
n(dextrose) = 0,27 mol.
Osmotic concentration (osmolarity)<span> is a measure of how many </span><span>osmoles of particles of solute</span><span> it contains </span>per liter.
The osmolarity = n(dextrose) ÷ V(solution).
The osmolarity = 0,27 mol ÷ 1 L.
The osmolarity = 0,27 mol/L · 1000 mmol/m.
The osmolarity (dextrose) = 270 mosm/L.
The osmolarity (dextrose monohydrate) = 50 g÷197 g/mol·1000 =254mosm/L
Answer:
2.99 atm
2279.43 torr
44.07 psi
Explanation:
Torr, atms and psi all units are units of pressure.
Conversion from KPa to atm:
1 KPa is equal to 0.00987 atm. To convert from KPa to atm we will multiply the given value with 0.00987 atm.
303.9 KPa × 0.00987 atm / 1 KPa
2.99 atm
Conversion from KPa to torr:
1 KPa is equal to the 7.5006 torr. To convert from KPa to torr we will multiply the KPa value by 7.5006.
303.9 KPa × 7.5006 torr/ 1 KPa
2279.43 torr
Conversion from KPa to psi:
psi is pound per square inch. 1 KPa is equal to the 0.1450 psi. To convert from KPa to psi we will multiply the KPa value by 0.1450 psi.
303.9 KPa × 0.1450 psi / 1 KPa
44.07 psi
Answer:
See explanation
Explanation:
In an atom, the inner electrons may shield the outer electrons from the attractive force of the nucleus. We, refer to this phenomenon as the <u><em>shielding effect</em></u>, It is defined as a decrease in the magnitude of attraction between an electron and the nucleus of an atom having more than one electron shell (energy level).
Shielding effect increases down the group due to addition of more shells but decreases across the period due to the increase in the size of the nuclear charge.
As the magnitude of shielding increases down the group, ionization of electrons becomes easier and the first ionization energies of elements decreases as we move down the group. Since shielding effect decreases across the period, the first ionization energies of elements increases across the period.
To find moles from any number of atoms, always divide by the constant called Avogadro's Number. This number is representative of the number of atoms or molecules in a mole of any substance and is equal to about
.
So, for this problem, we take the number of atoms of oxygen and divide by Avogadro's Number.
Answer: 0.661 moles (after rounding)
Make sense?
