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AysviL [449]
2 years ago
9

In which pair is each substance a mixture?

Chemistry
1 answer:
qaws [65]2 years ago
6 0

Answer:

Air & Water

Explanation:

Air and water is the common mixtures in the book of the book called "Science & Land"

You might be interested in
What Can bond together to form an ionic bond?
Kazeer [188]

Answer:

An ionic bond forms between two ions of opposite charges. In ionic bonding, electrons transfer from one atom to another. The elements take on either a negative or positive charge. Ions are another name for charged atoms. Some elements are electropositive, and some are electronegative.

Hope this helps!

5 0
3 years ago
What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?
devlian [24]

Answer:

T = 0.182 Kelvin

Explanation:

As we know that

PV = nRT\\

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin  

R is the gas constant  

V is the volume in liters

R = 0.08206

Substituting the given values in above equation, we get -

1.35 * \frac{50}{1000}= 4.5 * 0.08206* T\\

On rearranging, we get

T = \frac{1.35*50}{1000*0.08206*4.5} \\

T = 0.182 Kelvin

7 0
3 years ago
A transverse wave is traveling from north to south. Which statement could be true for the motion of the wave particles in the me
Agata [3.3K]
<span>C. Their direction of motion is south and north. </span>
7 0
3 years ago
The molecular weight of NaCl is 58.44 grams/moles. How many grams of NaCl are found in a beaket with 100 ml of a 0.0050 M soluti
Viktor [21]

Answer:

The mass of NaCl is 0.029 grams

Explanation:

Step 1: Data given

Molecular weight of NaCl = 58.44 g/mol

Volume of solution = 100 mL = 0.100 L

Molarity = 0.0050 M

Step 2: Calculate moles NaCl

Moles NaCl = molarity * volume

Moles NaCl = 0.0050 M * 0.100 L

Moles NaCl = 0.00050 moles

Step 3: Calculate mass NaCl

Mass NaCl = moles NaCl * molar mass NaCl

Mass NaCl = 0.00050 moles * 58.44 g/mol

Mass NaCl = 0.029 grams

The mass of NaCl is 0.029 grams

4 0
3 years ago
How do you know the ph level of 10^-8
sergiy2304 [10]

pH=6.98

Explanation:

This is a very interesting question because it tests your understanding of what it means to have a dynamic equilibrium going on in solution.

As you know, pure water undergoes self-ionization to form hydronium ions, H3O+, and hydroxide anions, OH−.

2H2O(l]⇌H3O+(aq]+OH−(aq]→ very important!

At room temperature, the value of water's ionization constant, KW, is equal to 10−14. This means that you have

KW=[H3O+]⋅[OH−]=10−14

Since the concentrations of hydronium and hydroxide ions are equal for pure water, you will have

[H3O+]=√10−14=10−7M

The pH of pure water will thus be

pH=−log([H3O+])

pH=−log(10−7)=7

Now, let's assume that you're working with a 1.0-L solution of pure water and you add some 10

5 0
3 years ago
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