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3 years ago

Basically im not smart ... I just Need to Know The Vertex

Mathematics

1 answer:

Olenka [21]3 years ago

5 0

It'd be AEC, the vertex are just the lines that create the point E

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Please help me with this

MrMuchimi

please mark this answer as brainlist

4 0

3 years ago

Sherese draws a segment and labels the endpoints R and S. She uses a compass and straightedge to construct a segment congruent t

Lisa [10]

Answer:

1. Adjust the compass opening to the width of RS

2. Draw point P anywhere

3. Place the compass point on point P and draw an arc.

4. Label any point on the arc as point Q

5. Use a straightedge to connect points P and Q

Step-by-step explanation:

I did the test. This was the right answer.

8 0

3 years ago

Read 2 more answers

I have no clue how to do this please help

mel-nik [20]

Answer:

Max = (6,0); min = (-2, 4)

Step-by-step explanation:

1. Summarize the constraints

$\text{Constraints} = \begin{cases}(a)\qquad 2x - y & \leq 12\\(b)\qquad 4x+ 2y & \geq 0\\(c) \qquad x + 2y & \leq 6\\ \end{cases}$

2. Optimization equation

z = 5x + 2y

3. Graph the constraints to identify the feasible region

See the figure below.

The "TRUE" regions for each graph are the shaded areas to the side of the line indicated by the arrows.

The "feasibility region" is the dark green area where all three areas overlap and all three conditions are satisfied.

5. Determine the points of intersection among the constraints

(i) Constraints (a) and (b)

$\begin{array}{rcr}2x - y & = & 12\\4x + 2y & = & 0\\4x - 2y & = & 24\\8x&=&24\\x & = & \mathbf{3}\\6 - y & = & 12\\-y & = &6\\y & = & \mathbf{-6}\\\end{array}\\$

The lines intersect at (3,-6).

(ii) Constraints (a) and (c)

$\begin{array}{rcr}2x - y & = & 12\\x + 2y & = & 6\\4x - 2y & = &24\\5x & = & 30\\x & = & \mathbf{6}\\6 + 2y & = & 6\\2y & = &0\\y & = & \mathbf{0}\\\end{array}$

The lines intersect at (6,0).

(iii) Constraints (b) and (c)

$\begin{array}{rcr}4x+ 2y &= & 0\\x + 2y &=& 6\\3x & = & -6\\x & = & \mathbf{-2}\\-2 +2y & = & 6\\2y & = &8\\y & = & \mathbf{4}\\\end{array}$

The lines intersect at (-2,4).

6. Determine the x- and y-intercepts of the feasible region

The five black dots at (3,-6), (6,0), and (-2,4) are the vertices of the polygon that represents the feasible region.

Each vertex is a possible maximum or minimum of z.

7. Calculate the maxima and minima

Calculate z at each of the vertices.

(i) At (-2,4)

z = 5x + 2y = 5(-2) + 2(4) = -10 + 8 = 2

(ii) At (3,-6)

z = 5(3) + 2(-6) = 15 - 12 = 3

(iii) At (6,0)

z = 5(6)+ 2(0) = 30 + 0 = 30

The maximum of z occurs at (6,0).

The minimum of z occurs at (-2, 4).

7 0

3 years ago

One step equation x - 17 = 10

Brrunno [24]

+17 bc you want to do the opposite so then it’s 17+10 which gets you x=27

3 0

2 years ago

As of a certain date, there had been a total of 14,649 performances of two shows on Broadway, with 2389 more performances of Sho

Naddik [55]

Subtract the difference:

14,649 - 2389 = 12,260

Divide that by 2

12,260 / 2 = 6,130

That is the number of shows for B.

For A add the 2,389 to the number of shows for B

2389 + 6130 = 8,519

Show A = 8,519

Show B = 6,130

4 0

3 years ago