Answer:
a. 300 Kg of fertilizer
b. 225 Kg of fertilizer
c. 400 Kg of fertilizer
d. 600 Kg of fertilizer
Explanation:
The percentage composition ratio of Nitrogen, Phosphorus and Potassium in a 1 Kg bag of the given fertilizer is 40:15:10.
Therefore a 1 Kg bag contains;
40/100 * 1 Kg = 0.4 Kg of Nitrogen;
15/100 * 1 Kg = 0.15 Kg of phosphorus;
10/100 * 1 Kg = 0.1 Kg of potassium
Quantity of fertilizer required to add to a hectare to supply;
a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer
b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer
c. Phosphorus at a rate of 60 kg/ha = 60/0.15 = 400 Kg of fertilizer
d. Potassium at a rate of 60 kg/ha = 60/0.1 = 600 Kg of fertilizer
The answer is na sodium, bromine
<u>Answer:</u> The molarity of anions in the solution is 0.0316 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of iron (II) chloride = 0.10 g
Molar mass of iron (II) chloride = 126.75 g/mol
Volume of solution = 50 mL
Putting values in above equation, we get:
1 mole of iron (II) chloride produces 1 mole of ions and 2 moles of ions
So, concentration of chloride ions (anions) in the solution =
Hence, the molarity of anions in the solution is 0.0316 M
1 mole of any substance is: 6.022*10²³ atoms or molecules.
9 moles of H₂S=9(6.022*10²³ molecules)=5.4198*10²⁴ molecules.
answer:there are 5.4198*10²⁴ molecules in 9.00 moles of H₂S.