Answer:
The overall speed add then divide
Hope this helped :)
Answer:
2584 g
Explanation:
The molecular formula for sucrose is C₁₂H₂₂O₁₁, which means its molar mass is 342.3 g/mol.
First we<u> convert molecules into moles</u> by using <em>Avogadro's number</em>:
- 4.55x10²⁴ molecules ÷ 6.023x10²³ mol/molecules = 7.55 mol
Now we <u>convert moles of sucrose into grams</u>, using its<em> molar mass</em>:
- 7.55 mol * 342.3 g/mol = 2584 g
Answer:
There will be 143,67g CO2 produced
Explanation:
2 C6H6 + 15 O2 → 12 CO2 + 6 H2O
(42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6
(113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2
0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.
(0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2
