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Troyanec [42]
3 years ago
9

The nucleus of an atom contains at least one proton. True or false

Chemistry
1 answer:
Svetllana [295]3 years ago
5 0
The answer is falling
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How many moles of air are necessary for the combustion of 5.00 molmol of isooctane, assuming that air is 21.0% O2O2 by volume?
Annette [7]

Answer:

67.5 moles of O2

Explanation:

2  C 8 H 18  +  27 O 2  →  16 C O 2  +  18 H 2 O

According to the balanced chemical equation, in normal air % moles of iso-octane will require 67.5 moles of oxygen to combust completely...

8 0
4 years ago
The plant structure that helps transport water and nutrients from the roots to the leaves and other parts of the plant is
devlian [24]
The answer is Xylem. The plant structure that helps transport water and nutrients from the roots to the leaves and other parts of the plant is Xylem.  In vascular plants, plants that have TUBELIKE STRUCTURES that carry water, nutrients, and other substances throughout the plant have xylem (<span>vascular tissue that carries water upward from the roots to every part of a plant) </span>and phloem (vascular tissue tubelike vessels that transport sugar made in photosynthesis from leaves to plant).
4 0
4 years ago
Read 2 more answers
According to the Arrhenius Theory a base reacts with an acid to produce
Novosadov [1.4K]
Water. Arrhenius acids provide a H+ ion and a base provides a OH- ion, which react to form water.
5 0
4 years ago
. How much energy is lost by a 30.0g sample of water that decreases in temperature from 56.7C to 25.0C?
lbvjy [14]

Answer:

Q = -3980.9 j

Explanation:

Given data:

Mass of sample = 30 g

Initial temperature = 56.7 °C

Final temperature = 25 °C

Specific heat of water = 4.186 j/g.°C

Amount of heat released = ?

Formula:

Q = m.c.ΔT

Q = heat released

m = mass of sample

c = specific heat of given sample

ΔT = change in temperature

Solution:

ΔT = T2 -T1

ΔT = 25 °C - 56.7 °C = - 31.7°C

Q = m.c.ΔT

Q = 30 g × 4.186 j/g.°C ×  - 31.7°C

Q = -3980.9 j

8 0
3 years ago
What is the kinetic energy, in joules, of a molecule of carbon tetrachloride moving at a speed of 255 m s–1 (use the appropriate
hram777 [196]

Answer:

The kinetic energy of a molecule of carbon tetrachloride is 8.29 zJ.

       

Explanation:

The kinetic energy of a molecule of carbon tetrachloride is given by:

K = \frac{1}{2}mv^{2}

Where:

m: is the mass

v: is the speed = 255 m/s                            

To find the mass we need to find the molar mass for CCl₄, and use the Avogadro's number, knowing that in 1 mol of carbon tetrachloride we have 6.022x10²³ molecules:

A (C) = 12.011 g/mol

A (Cl) = 35.45 g/mol

The molar mass (M) of CCl₄ is:

M = A (C) + 4*A (Cl) = 12.011 g/mol + 4*35.45 g/mol = 153.81 g/mol

Now, the mass of 1 molecule of CCl₄ is:

m = 153.81 \frac{g}{mol}*\frac{1 mol}{6.022 \cdot 10^{23} molecules} = 2.55 \cdot 10^{-22} g = 2.55 \cdot 10^{-25} kg

Finally, the kinetic energy of a molecule of carbon tetrachloride is:

K = \frac{1}{2}mv^{2} = \frac{1}{2}2.55 \cdot 10^{-25} kg*(255 m/s)^{2} = 8.29 zJ

Therefore, the kinetic energy of a molecule of carbon tetrachloride is 8.29 zeptoJoule.

I hope it helps you!

6 0
3 years ago
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