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3 years ago

Which of the following is NOT a type of mucle tissue?

Chemistry

2 answers:

padilas [110]3 years ago

8 0

Answer:

Striped should be the answer

lozanna [386]3 years ago

5 0

Skeletal is not a muscle tissue

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What bonds break? select that apply

igor_vitrenko [27]

Hydrogen-Hydrogen
Oxygen=Oxygen

7 0

4 years ago

For the simple decomposition reaction: AB(g) LaTeX: \longrightarrow⟶ A(g) + B(g), the rate = k{AB}2 ({ = [) and k = 0.85 1/MLaTe

Nesterboy [21]

Answer:

1.169s

Explanation:

k = 0.851 M-1s-1

The unit of the rate constant, k tells us this is a second order reaction.

From the question;

Initial Concentration [A]o = 2.01M

Final Concentration [A] = One third of 2.10 = (1/3) * 2.10 = 0.67M

Time = ?

The integrated rate law for second order reactions is given as;

1 / [A] = (1 / [A]o) + kt

Making t subject of interest, we have;

kt = (1 / [A] ) - (1 / [A]o )

t = (1 / [A] ) - (1 / [A]o ) / k

Inserting the values;

t = [ (1 / 0.67 ) - (1 / 2.10) ] / 0.851

t = ( 1.4925 - 0.4975 ) / 0.851

t = 0.995 / 0.851

t = 1.169s

[A] = 0.13073 M ≈ 0.13 M ( 2 s.f)

7 0

3 years ago

The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri

Nimfa-mama [501]

Answer: The expression for equilibrium constant is $\frac{[NH_3]^2}{[H_2]^3[N_2]}$

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as $k_c$

For a general reaction:

$aA+bB\rightleftharpoons cC+dD$

The equilibrium constant is written as:

$k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

Chemical reaction for the formation of ammonia is:

$N_2+3H_3\rightleftharpoons 2NH_3$

$k_c=1.6\times 10^2$

Expression for $k_c$ is:

$k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

$1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

8 0

3 years ago

Can anyone solve #2 or #3 i cannot figure them out

kompoz [17]

Answer:

sorry,,,,I can't

Explanation:

8 0

3 years ago

PLEASE HELP ASAP

Inessa05 [86]

The enthalpy change for the reaction 2K + S + K2S using the following thermochemical reactions is mathematically given as

dn=70.7kg

<h3>What is the enthalpy change for the reaction?</h3>

Generally, the equation for the Chemical reaction is mathematically given as

2k+s----->K2S

Therefore

KS+K----->K2S

Therefore

dn=dn1+dn2

dn=32.5+38.2

dn=70.7kg

In conclusion, the enthalpy change is

dn=70.7kg