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Ksju [112]
2 years ago
11

Which of the following is NOT a type of mucle tissue?

Chemistry
2 answers:
padilas [110]2 years ago
8 0

Answer:

Striped should be the answer

lozanna [386]2 years ago
5 0
Skeletal is not a muscle tissue
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Hydrogen and oxygen are different elements ...
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Composition about my favorite sport in french​
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Le football est mon sport préféré. C'est aussi un sport célèbre dans le monde entier. En jouant au football, nous pouvons garder notre corps fort, en forme et flexible, jouer au football est un bon exercice et bon pour la santé. Il a besoin d'un terrain spacieux. Le nombre de joueurs nécessaires pour ce jeu est de vingt-deux. Il y a deux groupes. Chaque groupe compte onze joueurs. Chaque groupe a un gardien de but. Il y a un centre à partir duquel le jeu commence avec l'arbitre. Il a le pouvoir de commenter le bien ou le mal. Les joueurs doivent respecter les règles du sport. Si un joueur lui désobéit, il est disqualifié et sort du terrain de jeu. Lorsque le but est marqué des supporters, la joie n’a pas de limite. Des applaudissements passionnants sont visibles lorsqu'un but est marqué. Cette pièce est originaire d'Angleterre. Ensuite, il s'est répandu dans presque tous les coins et recoins du monde. Sa popularité augmente de jour en jour.

3 0
2 years ago
If you had a sample containing 55 alpha particles, how many protons would be present in that sample? Show all necessary work.
arlik [135]
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8 0
3 years ago
I.j Thompson’s experiments provided evidence that an atom
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2 years ago
The first-order rate constant for the reaction of methyl chloride (CH3Cl) with water to produce methanol (CH3OH) and hydrochlori
Dvinal [7]

Answer:

K(48.5°C) = 1.017 E-8 s-1

Explanation:

  • CH3Cl + H2O → CH3OH + HCl

at T1 = 25°C (298 K) ⇒ K1 = 3.32 E-10 s-1

at T2 = 48.5°C (321.5 K) ⇒ K2 = ?

Arrhenius eq:

  • K(T) = A e∧(-Ea/RT)
  • Ln K = Ln(A) - [(Ea/R)(1/T)]

∴ A: frecuency factor

∴ R = 8.314 E-3 KJ/K.mol

⇒ Ln K1 = Ln(A) - [Ea/R)*(1/T1)]..........(1)

⇒ Ln K2 = Ln(A) - [(Ea/R)*(1/T2)].............(2)

(1)/(2):

⇒ Ln (K1/K2) = (Ea/R)* (1/T2-1/T1)

⇒ Ln (K1/K2) = (116 KJ/mol/8.3134 E-3 KJ/K.mol)*(1/321.5 K - 1/298 K)

⇒ Ln (K1/K2) = (13952.37 K)*(- 2.453 E-4 K-1)

⇒ Ln (K1/K2) = - 3.422

⇒ K1/K2 = e∧(-3.422)

⇒ (3.32 E-10 s-1)/K2 = 0.0326

⇒ K2 = (3.32 E-10 s-1)/0.0326

⇒ K2 = 1.017 E-8 s-1

7 0
3 years ago
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