Most likely b,c or d sorry but idk I’m just helping other people answer by eliminating one answer
Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,
pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
Now put all the given values in this expression, we get:
![6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=6.0%3D8.0%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
![\frac{[Deprotonated]}{[Protonated]}=0.01](https://tex.z-dn.net/?f=%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D%3D0.01)
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
![\frac{[Protonated]}{[Deprotonated]}=100](https://tex.z-dn.net/?f=%5Cfrac%7B%5BProtonated%5D%7D%7B%5BDeprotonated%5D%7D%3D100)
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100
Fat and soap are different substances. <span>One reason is that they have a different malleability. The Soap is very hard and sturdy. The fat is soft. Also, soap and fat are different because they had different smells. The soap had a refreshing smell and a soapy one and the fat smelled rubbery like Play-doh. Another reason why fat and soap are different substances is that they don’t dissolve the same in water and oil. Soap is soluble in water and shortening is not soluble in water. Soap is not soluble in oil and shortening is soluble in oil. In the water shortening did not become cloudy but soap did. When placed in oil, the shortening disappeared completely, while soap did not change at all.The melting point of the fat was 57.6 we could not find the melting point of the soap. The soaps melting point is higher than the water's boiling point. A property is something that describes an object and does not change. For example, the soap is white, where the fat is off white. Color is a property. Fat and soap are also different because they have different densities. The soap sank but the fat floated. The density of fat is about .88 g/ml and the density of soap is about 1.18 g/ml. </span><span>Fat and soap are not the same substances one reason is they have different properties.Malleability, hardness, solubility, melting point,color, and density are all properties. </span>A property is a characteristic of a substance that does not change. Different substances have different properties.<span> If they had the same properties, they would be the same substance, but, since they don’t, they are different substances.
Hope this helps :D</span>
8 moles of water on the right side.
An oxidation-reduction or redox reaction is a reaction that involves the transfer of electrons between chemical items (the atoms, ions, or molecules involved in the reaction).
Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.
Step 1:
MnO4- ----> Mn2+
2Cl- ------> Cl2
Step 2:
MnO4- --> Mn2+ + 4H2O
2Cl- -----> Cl2
Step 3:
8H+ + MnO4- ------> Mn2+ + 4H2O
2Cl- ----->Cl2
Step 4:
8H+ + MnO4- +5e- ------>Mn2+ + 4H2O
2Cl- ----> Cl2+ 2e-
Step 5:
16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2
This is the balanced equation in an acidic medium.
That is 8, right side.
To know more about redox reaction follow the link:
https://brainly.in/question/9854479
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If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish equilibrium. If a chemical reaction is at equilibrium and experiences a change in pressure, temperature, or concentration of products or reactants, the equilibrium shifts in the opposite direction to offset the change. This page covers changes to the position of equilibrium due to such changes and discusses briefly why catalysts have no effect on the equilibrium position.
For example, if the system is changed in a way that increases the concentration of one of the reacting species, it must favor the reaction in which that species is consumed. In other words, if there is an increase in products, the reaction quotient, Qc, is increased, making it greater than the equilibrium constant, Kc.
