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Troyanec [42]
3 years ago
7

Emanuel added two integers.

Mathematics
1 answer:
Temka [501]3 years ago
7 0
A. When you add to negative numbers, it is always negative. A positive + a positive is positive. In D, the answer is always 0. 1 + -1 is 0. In C, it varies. The bigger number not including the negative sign is the sign the number has. For example, -6 + 5 = -1. 6 is bigger than 5. You subtract the smaller number from the bigger number and that is the answer. You would then tack on the negative sign because it is -6, and 6 is bigger than 5.
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Step-by-step explanation:


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Answer:

a) P(X\geq 3.5)=P(\frac{X-\mu}{\sigma}\geq \frac{3.5-\mu}{\sigma})=P(Z\geq \frac{3.5-5.0}{1.2})=P(Z\geq -1.25)

And we can find this probability using the z table or excel

P(Z \geq

b) P(X\leq 6.0)=P(\frac{X-\mu}{\sigma}\leq \frac{6.0-\mu}{\sigma})=P(Z\leq \frac{6.0-5.0}{1.2})=P(Z\leq 0.833)

And we can find this probability using the z table or excel:

P(Z \leq

c) P(3.5

And we can find this probability on this way:

P(-1.25

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1.25

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the interest rate of a population, and for this case we know the distribution for X is given by:

X \sim N(5.0,1.2)  

Where \mu=5.0 and \sigma=1.2

We are interested on this probability

P(X\geq 3.5)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X\geq 3.5)=P(\frac{X-\mu}{\sigma}\geq \frac{3.5-\mu}{\sigma})=P(Z\geq \frac{3.5-5.0}{1.2})=P(Z\geq -1.25)

And we can find this probability using the z table or excel

P(Z \geq

Part b

We are interested on this probability

P(X\leq 6.0)

P(X\leq 6.0)=P(\frac{X-\mu}{\sigma}\leq \frac{6.0-\mu}{\sigma})=P(Z\leq \frac{6.0-5.0}{1.2})=P(Z\leq 0.833)

And we can find this probability using the z table or excel:

P(Z \leq

Part c

P(3.5

And we can find this probability on this way:

P(-1.25

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1.25

8 0
3 years ago
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