We have been given that from a pool of 12 candidates, the offices of president, vice-president, secretary, and treasurer will be filled. We are asked to find the number of ways in which the offices can be filled.

We will use permutations for solve our given problem.

$^nP_r=\frac{n!}{(n-r)!}$ , where,

n = Number of total items,

r = Items being chosen at a time.

For our given scenario $n=12$ and $r=4$ .

$^{12}P_4=\frac{12!}{(12-4)!}$

$^{12}P_4=\frac{12!}{8!}$

$^{12}P_4=\frac{12*11*10*9*8!}{8!}$

$^{12}P_4=12*11*10*9$

$^{12}P_4=11,880$

Therefore, offices can be filled in 11,880 different ways.

3 0

3 years ago

Find slope of a line perpendicular to each given

statuscvo [17]

82 is the answer now sub to pooi thegreat on yt

5 0

3 years ago

julia is putting together bag of 45 blocks. if she wants the probability of choosing a red block to be 1/5 how many red blocks j

4vir4ik [10]

Answer:

Step-by-step explanation:

Given that the sample size is 45 blocks

Let number of red blocks in the bag to be x

Then the probability of chosing a red block will be x/45

Given that the probability of choosing a red block is 1/5 then you can form the expression;

x/45 = 1/5 ---------------find the value of x by performing cross multiplication

5x=45*1

5x/5=45/5

x=9

Answer

Julia put 9 red blocks in the bag.

7 0

3 years ago