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jolli1 [7]
3 years ago
8

How do I solve number 1

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0
Because he ended up paying $24 more than the actual price of the drill, this is the amount of interest he paid.

In total, the repairman pays $324 in 6 equal payments. So, each payment was \dfrac{\$324}6=\$54.
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Find x in the diagram below. T 1 35.4° 20.2° 252​
Colt1911 [192]

Answer:

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Find the unknown measure.
stira [4]

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m arc PR = 36°

Step-by-step explanation:

∠QTS = 1/2 * (arc QS + arc RP)

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3 0
3 years ago
117. Sami opens an account and deposits $100 into it at the end of each month. The account earns 2% per year compounded monthly.
Sergio [31]

Answer:

The explicit function is:

S_{n} =Pz^{n-1} +C(\frac{z^{n-1}-1}{z-1} )

where

z=(1+\frac{0.02}{12})

and we calculate S12:

S_{12} = $1211.06

Step-by-step explanation:

Expanding a few steps of the compound interest:

S_{1}=100\\S_{2}=S_{1}(1+\frac{0.02}{12})+100\\S_{3}=S_{2}(1+\frac{0.02}{12})+100\\...\\S_{n}=S_{n-1}(1+\frac{0.02}{12})+100

We can write:

(1+\frac{0.02}{12})=z

100=C for deposits

Then, expanding the previous equations would yield:

S_{1}=C\\S_{2}=Cz + C\\S_{3}=Cz^{2}+Cz + C\\S_{n}=Cz^{n-1} +...+Cz+C

This is a geometric series form, which can be simplified to:

S_{n}=C(\frac{z^{n}-1}{z-1} )

plugin in the values for the 12 month gives:

S_{12}=100(\frac{(1+\frac{0.02}{12})^{12} -1}{\frac{0.02}{12}})=1211.0613

6 0
3 years ago
How can this expression be solved? please help
loris [4]

Answer: if you know the square find the GCF

Step-by-step explanation: List the prime factors of each number.

Circle every common prime factor — that is, every prime factor that's a factor of every number in the set.

Multiply all the circled numbers. The result is the GCF. Remember, the square of a number is that number times itself. The perfect squares are the squares of the whole numbers. The square root of a number, n, written below is the number that gives n when multiplied by itself.

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3 years ago
Johnny was able to drive an average of 23 miles per hour faster in his car after the traffic cleared. He drove 30 miles in traff
Vikentia [17]
Jonny s speed was 30mph
4 0
3 years ago
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