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Yuliya22 [10]
3 years ago
7

Each car can hold 5 students and each minibus can hold 15 students.

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer:

5x+15y=85

Step-by-step explanation:

X and Y are the unknown variables, just add them to 5,(cars), and 15 (minibus)

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45+ 46+47+ 48+ ... 113 + 114Gauss approach
Doss [256]

Answer:

5565

Step-by-step explanation:

1+2+3+4...+113+114=\frac{114*115}{2} =6555

1+2+3+4 ... +43+44=\frac{44*45}{2} =990

Thus, 45+46+47+48...+113+114= 6555-990=5565

3 0
3 years ago
Which graph best represents the equation created when the slope of y = 6x is changed to 0?
luda_lava [24]

The graph with an equation y = 6x has a slope of 6. If the slope is changed to 0, the equation becomes y = 0.

<h3>What is a linear function?</h3>

A linear function is in the form:

y = mx + b

Where m is the slope (rate of change) and b is the y intercept

The graph with an equation y = 6x has a slope of 6. If the slope is changed to 0, the equation becomes y = 0.

Find out more on linear function at: brainly.com/question/4025726

5 0
2 years ago
Find the area of the trapezoid to the nearest tenth.
erica [24]

Answer:

2.2 metres squared

Step-by-step explanation:

We need to find the area of this trapezoid.

The area of a trapezoid is denoted by:

A=\frac{(b_1+b_2)h}{2}, where b_1 and b_2 are the parallel bases and h is the height

Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.

Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:

2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4

Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:

A=\frac{(b_1+b_2)h}{2}

A=\frac{(0.9+2.3)*1.4}{2}=2.2

The answer is thus 2.2 metres squared.

<em>~ an aesthetics lover</em>

8 0
3 years ago
"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year
KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that p = 0.56

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is P(X \geq 1) when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0
3 years ago
PLS HELP IF U TAKE THE POINTS IM REPORTING U<br> QUESTION IN PIC
3241004551 [841]
The answer should be false
3 0
3 years ago
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