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KengaRu [80]
3 years ago
15

Write in standard form 4.91E-2

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

4.91e-2 in decimal form is 0.0491

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Every triangle in the figure at right is equilateral. What is the measure of ∠AGE?
Andrew [12]

Answer:

120°

Step-by-step explanation:

All the angles of an equilateral triangle are equal, and hence have a measure of 60°.

∵ ∠AGF is a part of equilateral Δ AGF, m∠AGF = 60°.

∵ ∠FGE is a part of equilateral Δ AGF, m∠FGE = 60°.

Also note that ∠AGE = ∠AGF + ∠FGE.

⇒ m∠AGE = m∠AGF + m∠FGE

⇒ m∠AGE  = 60° + 60°

                    = 120°.

7 0
3 years ago
M is the midpoint of C(1,7) and D(-8,-3). Find the coordinates of M.
Alex73 [517]

Answer:

hello I hope the image helps

5 0
1 year ago
What is 5/12 divided by 3/16 as a fraction?
GuDViN [60]
<span>The answer is
= 20/9
=2 2/9</span>
8 0
3 years ago
Read 2 more answers
20 points and brainliest <br> I’m in quiz in need it asap <br> Number 4
iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

Now, in the last step I've used the fact that e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z, or in other words, the complex exponential is periodic with 2\pi as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0
2 years ago
1.6x=1.28<br> help me solve this
bogdanovich [222]

Answer:

Step-by-step explanation:

Sure! So, we need to divide by 1.6 on each side to isolate the x.

1.6x / 1.6 is just x. We need to divide by the same on the other side too!

1.28 / 1.6 is 0.8.

So x = 0.8

7 0
3 years ago
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