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4 years ago

How do you simplify a square root?

Mathematics

1 answer:

Ksivusya [100]4 years ago

6 0

Answer:

Step-by-step explanation:

To simplify a square root, there will be 2 options after it is simplified. One is positive and the other is negative

For example, The square root of 4 would be equal to 2 or -2

Hope this help you :3

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From delta math:<br> Subtract -2x^2 + 3x - 9 from 8x^2 + 10x - 10

Leto [7]

Answer:

$10x^2 + 7x - 1$

Step-by-step explanation:

Step 1: Build the expression in numerical form.

$(8x^2 +10x - 10) - (-2x^2 + 3x - 9)$

Step 2: Distribute the negative sign.

$8x^2 +10x -10 + (-1)(-2x^2) + (-1)(3x) + (-1)(-9)$
$8x^2 + 10x - 10 + 2x^2 + (-3x) + 9$

Step 3: Combine like terms.

$(8x^2 +2x^2) + (10x -3x) + (-10+9)$
$10x^2 +7x -1$

Therefore, the answer is $10x^2 + 7x -1$ .

4 0

3 years ago

I need help with these

IrinaVladis [17]

Let x be the number.
"twelve decreased by twice a number" ---> 12 - 2x
"8 times the sum of number and 4" ---> 8(x + 4)
12 - 2x = 8(x + 4)
12 - 2x = 8x + 32 (distributive property)
12 = 10x + 32 (add 2x to both sides)
-20 = 10x (subtract 32 from both sides)
x = -2 (divide both sides by 10)

6 0

3 years ago

Read 2 more answers

What is 53.67 to one decimal place

MAXImum [283]

53.67 to one decimal place is 53.7 since you round the .6 to the .7

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3 years ago

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Solve the inequality <br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7Bx%20%2B%203%7D%20%20%5Cleqslant%203" id="Tex

Fofino [41]

$Domain:x\neq-3\\\\\dfrac{2x}{x+3}\leq3\qquad\text{subtract 3 from both sides}\\\\\dfrac{2x}{x+3}-3\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3(x+3)}{x+3}\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3x+9}{x+3}\leq0\\\\\dfrac{2x-(3x+9)}{x+3}\leq0\\\\\dfrac{2x-3x-9}{x+3}\leq0\\\\\dfrac{-x-9}{x+3}\leq0\Rightarrow(x+3)(-x-9)\leq0\\\\x=-3,\ x=-9\\\\x\in(-\infty,\ -9]\ \cup\ (-3,\ \infty)$

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3 years ago

Please help with 14-17!!

rodikova [14]

14 is always 15 is sometimes 16 is sometimes

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3 years ago