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katovenus [111]
3 years ago
6

Jasmine is baking and selling cupcakes for $15 per dozen. She would like to make more than $120 in cupcake sales. Which number l

ine below represents the solutions to this situation?
Mathematics
1 answer:
ELEN [110]3 years ago
5 0
Jasmine is baking and selling cupcakes for $15 per dozen.
Let x be the number of dozens of cupcake made by Jasmine.
Her total sales= Sales Per Dozen X Number of Dozens of cupcake sold
= $15 X x = $15x
Since she would like to make more than $120 in cupcake sales.
It means her total sales must be greater than $120.
15x>120
x>120/15
x>8
The number line attached represents the solutions to the situation.
All integers to the right of 8 (excluding 8) satisfies the situation.

Hope this helps!:)
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80 is 32% of what number
Sveta_85 [38]
We set up a proportion: 80/?= 32/100

Cross multiply: 32*?= 80*100
⇒ ?= 80*100/32= 250

80 is 32% of 250.
7 0
3 years ago
Read 2 more answers
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
4 years ago
the area of a room in a dollhouse is 1248 square inches. the width of the room is 8 inches . how long is the room?
geniusboy [140]

Answer:

156

Step-by-step explanation:

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3 0
3 years ago
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To find out how many gallons of gas the car will hold, divide the total number of miles traveled on one tank of gas by the average miles per gallon.
675/45 = g
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The tank can hold 15 gallons of gas.
8 0
4 years ago
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ycow [4]

Answer:

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Step-by-step explanation:

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5 0
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