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irakobra [83]
2 years ago
12

A running trail is 63 miles long. Leigh plans on

Mathematics
2 answers:
ivann1987 [24]2 years ago
8 0

Answer:15.75

Step-by-step explanation:63/4 = 15.75

nadezda [96]2 years ago
4 0

Answer:

63/4 or 15 3/4 miles each day

Step-by-step explanation:

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50 (x+ 10) = 240<br> Whats the value for x
Katen [24]

Answer:

-26/5 or -5.2

Step-by-step explanation:

First, you need to expand the parentheses:

50x+500=240

Now, subtract 500 from both sides:

50x=-260

Now, divide both sides by 50

x=-26/5=-5.2

Hope this helps!

3 0
3 years ago
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Write an equation of the line in slope-intercept form (2,1) and (0,-3)
Snowcat [4.5K]

Answer:

y = 2x - 3

Step-by-step explanation:

7 0
2 years ago
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Can anyone help me with this?0​
sergeinik [125]

Answer:

C) (y - 1)(y - 5)

Step-by-step explanation:

Hi there!

First you separate your expression into groups.

(y^2-5y)(-1y+5)

Now we take the common multiple out of each.

y(y - 5)-1(y - 5)

Since we have two (y - 5)s, we can pull it out of the equation as its own common multiple.

After we do that, we are left with y - 1. (we got this from taking the common multiples out)

Now we are just left with (y - 5)(y - 1)

Hope this helped!

4 0
2 years ago
James has $7.60 in nickels and quarters. He has 4 fewer nickels than quarters. How many of each coin does he have? ​
Rainbow [258]
26 quarters, 22 nickels
4 0
2 years ago
11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *
kompoz [17]

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

3 0
3 years ago
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