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RoseWind [281]
3 years ago
9

Derivatives of sin(logx) from first principle​

Mathematics
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

cos(logx)*(1/x)

Step-by-step explanation:

(sin(logx))'=cos(logx)*logx'=cos(logx)*(1/x)

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