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kondaur [170]
3 years ago
7

According to the bar graph above, which salary range is the least frequent?

Mathematics
1 answer:
Elis [28]3 years ago
5 0

9514 1404 393

Answer:

  D.  $101,000 – $120,000

Step-by-step explanation:

The bar graph is not completely labeled, but in the context of the question it seems safe to assume that the vertical scale can be considered to represent relative frequency.

So, the shortest bar is the one with the lowest frequency. The horizontal scale identifies that as 101-120. If we assume that is salary in thousands of dollars, then Choice D is appropriate.

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When you draw a circle and two of its diameters and connect the end points of the diameters what quadirateral do you get?
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A vin diagram I'm pretty sure. or maybe drugs pflucked my brain up. js
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Simplify 24 – 6x – 18 + 5x<br><br> 3 – 3x<br><br> –x + 6<br><br> 2x – 3<br><br> –4x – 17
Svetach [21]

= <span><span>−x</span>+6</span>

<span>=<span><span> −<span>3x</span></span>+3</span></span>

<span>= </span><span><span>−x</span>+6</span>
= <span><span>2x</span>−3</span>

<span>= <span><span>−<span>4x</span></span>−<span>17</span></span></span>


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3 years ago
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Nimfa-mama [501]

Answer:

414

Step-by-step explanation

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4 0
3 years ago
Read 2 more answers
A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one
kari74 [83]

Answer:

The probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

P(X)=p=\frac{1}{5}=0.20

There are <em>n</em> = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.20.

The probability mass function of <em>X</em> is:

P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...

Compute the probability that the student answers at least seventeen questions correctly as follows:

P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)

=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}

Thus, the probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

4 0
3 years ago
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Harlamova29_29 [7]
As it is only 5, it is 5/1 so you do 5 x 3 = 15 then 1 x 4 = 4. So 15/4
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