Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:
Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
2 42/100 turn it to a fraction
Answer:
Step-by-step explanation:
Y = kxz
Putting values of y x and z in the equation
4 = k(2)(3)
4 = k6
2/3 = k
Now finding y when x = - 6 and z = 2
Y = kxz
= 2/3(-6)(2)
= - 8