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geniusboy [140]
3 years ago
7

Chegg All of the following compounds are soluble in water except ____ . KClO4 Ba(OH)2 KCl PbCl2 AgNO3

Chemistry
1 answer:
EastWind [94]3 years ago
6 0

Answer:

The answer is "PbCl_2"

Explanation:

The water solution of PbCl2 is poor. It also has 2 distinct dissolving properties. In cold water, this will not dissolve easily.It is water-insufficiently soluble. And that in cold water, it is indeed insoluble. That's why we know that all energy should be available for a solid to dissolve in the liquid to counteract that attractive force between the ions in the grid.

You might be interested in
In which grouping of the periodic table do the elements have similar properties?
Valentin [98]

Answer:

only columns

Explanation:

All atoms of elements present in same group or column having same number of valance electrons. Thus the elements in same group having same properties.

For example:

Consider the second group. It consist of alkaline earth metals. There are six elements in second group. Beryllium, magnesium, calcium, strontium, barium and radium.

All have two valance electrons.

Electronic configuration of Beryllium:

Be = [He] 2s²

Electronic configuration of magnesium.

Mg = [Ne] 3s²

Electronic configuration of calcium.

Ca = [Ar] 4s²

Electronic configuration of strontium.

Sr = [Kr] 5s²

Electronic configuration of barium.

Ba = [Xe] 6s²

Electronic configuration of radium.

Ra = [ Rn] 7s²

They are present in group two and have same number of valance electrons (two valance electrons) and show similar reactivity.

They react with oxygen and form oxide.

2Ba   +   O₂   →    2BaO

2Mg  +   O₂   →    2MgO

2Ca +   O₂   →    2CaO

this oxide form hydroxide when react with water,

BaO  + H₂O   →  Ba(OH)₂

MgO  + H₂O   →  Mg(OH)₂

CaO  + H₂O   →  Ca(OH)₂

With sulfur,

Mg + S   →  MgS

Ca + S   →  CaS

Ba + S   →  BaS

5 0
4 years ago
How many atoms are present in 98.1 grams of Ar? You may report your numerical answer in scientific notation use e-notation.
Andrei [34K]

Answer:

1.48 × 10²⁴ atoms

Explanation:

Step 1: Calculate the moles of argon

Argon is a noble gas, whose molar mass is 39.95 g/mol. We will use this data to find the moles corresponding to 98.1 grams of argon.

98.1g \times \frac{1mol}{39.95g} =2.46 mol

Step 2: Calculate the atoms of argon

In order to calculate the number of atoms of argon in 2.46 moles of argon, we have to consider the Avogadro's number: there are 6.02 × 10²³ atoms of Ar in 1 mole of Ar.

2.46mol \times \frac{6.02 \times 10^{23}atoms  }{1mol} = 1.48 \times 10^{24}atoms

6 0
3 years ago
An alum hydrate sample was analyzed by decomposition and gave the following data:
xz_007 [3.2K]

Answer:

No, the experimental result is different from the theoretical value.

Explanation:

Based on the given information, the mass of beaker and watchglass plus alum hydrate is 102.218 grams, and the mass of beaker and watchglass is 101.286 grams. Therefore, the mass of alum hydrate is:  

= 102.218 grams - 101.286 grams

= 0.932 grams

Now the mass of anhydrous compound is,  

= 102.218 grams - 101.798 grams

= 0.42 grams

Thus, the mass of water present is,  

= 0.932 grams - 0.42 grams

= 0.512 grams

The mass percent of water is,  

= mass of water/Total mass of hydrate * 100

= 0.512 grams / 0.932 grams * 100

= 54.93 %

Hence, the experimental result in not similar to the theoretical result.  

7 0
3 years ago
Some instruments differentiate individual quanta of electromagnetic radiation based on their energies. assume such an instrument
bulgar [2K]

Answer:

5.68×10¯¹⁰ m

Explanation:

From the question given above, the following data were obtained:

Energy (E) = 3.50×10¯¹⁶ J

Wavelength (λ) =?

Energy (E) and wavelength (λ) are related according to the following formula:

E = hv/λ

Where

E => is the energy

h => is the Planck's constant

v => is the velocity of electromagnetic radiation

λ => is the wavelength of the radiation.

With the above formula, we can obtain the wavelength of the radiation as follow:

Energy (E) = 3.50×10¯¹⁶ J

Planck's constant (h) = 6.63×10¯³⁴ Js

Velocity (v) = 3×10⁸ m/s

Wavelength (λ) =?

E = hv/λ

3.50×10¯¹⁶ = 6.63×10¯³⁴ × 3×10⁸ / λ

3.50×10¯¹⁶ = 1.989×10¯²⁵/ λ

Cross multiply

3.50×10¯¹⁶ × λ = 1.989×10¯²⁵

Divide both side by 3.50×10¯¹⁶

λ = 1.989×10¯²⁵ / 3.50×10¯¹⁶

λ = 5.68×10¯¹⁰ m

Thus, the wavelength of the radiation is

5.68×10¯¹⁰ m

7 0
3 years ago
Use the drop-down menus to select the names of the labeled structures.<br><br> A: B: C:
Naya [18.7K]

Answer:

A Petal B Stigma C Stamen

Explanation:

5 0
3 years ago
Read 3 more answers
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