Answer:
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The balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid is:
Sodium hydroxide + Sulfuric acid → Sodium sulfate +water
<h3>What is the balanced molecular equation?</h3>
A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.
In the given reaction, the reactants have been sulfuric acid and sodium hydroxide. Thus, these are written on the left side of the right arrow. The sodium sulfate and water have been the products and written on the right side of the right arrow.
The balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid is:
Sodium hydroxide + Sulfuric acid → Sodium sulfate +water
Learn more about balanced molecular equations here:
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65.38 u ± 0.002 u there you go
Answer:
Explanation:
<u>1. Mass of water removed</u>
- Mass of water removed = mass of the evaporating dish and the sample of hydrate - mass of the evaporating dish and the sample after heating
- Mass of water evaporated = 16.864 g - 11.13 g = 5.734 g
This amount must be rounded to two decimals, because the least precise measure (11.13 g) contains two decimals.
- Mass of water evaporated = 5.73 g
<u>2. Moles of water removed from the sample by the heating process</u>
You must use the molar mass of water to convert 5.73 g of water to number of moles.
- Molar mass of water: 18.015 g/mol
- Number of moles = mass in grams / molar mass = 5.73 g / 18.015 g/mol = 0.318 moles.
