Question

How many atoms are present in 98.1 grams of Ar? You may report your numerical answer in scientific notation use e-notation.

Answer 1

Answer:

1.48 × 10²⁴ atoms

Explanation:

Step 1: Calculate the moles of argon

Argon is a noble gas, whose molar mass is 39.95 g/mol. We will use this data to find the moles corresponding to 98.1 grams of argon.

$98.1g \times \frac{1mol}{39.95g} =2.46 mol$

Step 2: Calculate the atoms of argon

In order to calculate the number of atoms of argon in 2.46 moles of argon, we have to consider the Avogadro's number: there are 6.02 × 10²³ atoms of Ar in 1 mole of Ar.

$2.46mol \times \frac{6.02 \times 10^{23}atoms }{1mol} = 1.48 \times 10^{24}atoms$