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topjm [15]
3 years ago
5

Find the x- and y-intercepts of the function f(x) = log(2x + 1) − 1.

Mathematics
1 answer:
Vilka [71]3 years ago
6 0

Answer:

(9/2,0) and (0,-1)

Step-by-step explanation:

y(0) = log(1)-1 = -1

y=0 when log(2x+1) = 1

2x+1 = 10

x = 9/2

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Answer:

((2 x^2 + 1)^2)/(x^2)

Step-by-step explanation:

Simplify the following:

(2 x + 1/x)^2

Hint: | Put the fractions in 2 x + 1/x over a common denominator.

Put each term in 2 x + 1/x over the common denominator x: 2 x + 1/x = (2 x^2)/x + 1/x:

((2 x^2)/x + 1/x)^2

Hint: | Combine (2 x^2)/x + 1/x into a single fraction.

(2 x^2)/x + 1/x = (2 x^2 + 1)/x:

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Hint: | Distribute exponents over quotients in ((2 x^2 + 1)/x)^2.

Multiply each exponent in (2 x^2 + 1)/x by 2:

Answer: ((2 x^2 + 1)^2)/(x^2)

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