Answer is 9
Step by step explanation
As CB is radius CB=3, CA=3+7=10
X^2=(7+3)^2-3^2=100-9=81
X=9
Answer:
The correct answer is;
No, the quadrilateral is not always a parallelogram
Step-by-step explanation:
Since there are only four opposite angles in a quadrilateral there are only two possible angle bisectors of the opposite angles also, the angle bisectors of a pair of opposite angles of a quadrilateral will intersect within the quadrilateral and therefore they cannot form the sides of a parallelogram
Therefore, the answer is no, the quadrilateral is not always a parallelogram.
(3,2),(-9,6)
slope = (6 - 2) / (-9 - 3) = -4/12 = -1/3
y = mx + b
slope(m) = -1/3
use either of ur points...(3,2)....x = 3 and y = 2
now we sub into the formula and find b, the y int
2 = -1/3(3) + b
2 = -1 + b
2 + 1 = b
3 = b
so ur equation is : y = -1/3x + 3 <==
Answer:
4. 6/15
Step-by-step explanation:
5. 5/3 is the an answer
Cos 52 = 0.6157
sin 42 = cos 48 = 2/3 (because 42 + 38 = 90 - complementary angles)
if tan 20,5 = 3/8 then tan 69.5 wil = 1 / 3/8 = 8/3