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creativ13 [48]
3 years ago
13

Which function is the inverse of f(x)=-x³-9?​

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

Inverse of f(x)=-x^3-9 is f^{-1}(x)=\sqrt[3]{-x-9}

Option B is correct option.

Step-by-step explanation:

We need to find inverse of f(x)=-x^3-9

For finding the inverse replace f(x) with y

y=-x^3-9

Now, solve for x

Adding 9 on both sides

y+9=-x^3-9+9\\y+9=-x^3

Multiply both sides by -1

-(y+9)=x^3\\x^3=-y-9

Taking cube root on both sides:

x^3=-y-9\\\sqrt[3]{x^3} =\sqrt[3]{-y-9} \\x=\sqrt[3]{-y-9}

Now replace x with f^{-1}(x) and y with x

f^{-1}(x)=\sqrt[3]{-x-9}

So, inverse of f(x)=-x^3-9 is f^{-1}(x)=\sqrt[3]{-x-9}

Option B is correct option.

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c. 5

Step-by-step explanation:

1.5m = 1.5*100 cm = 150 cm

Divide 150 cm by 30 cm,

150/30 = 5

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Step-by-step explanation:

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3 years ago
What is your sister’s total cost under each of the two plans?2. Suppose your sister doubles her monthly usage to 3,500 minutes a
chubhunter [2.5K]

Answer:

(1) The total cost under Plan A is <u>$92</u> and the total cost under Plan B is <u>$515</u>.

(2) The total cost under Plan A is <u>$92</u> and the total cost under Plan B is <u>$1,030</u>.

Step-by-step explanation:

<u><em>The question is incomplete, so the complete question is below:</em></u>

A\ cell \ phone \ company\  offers\  two \ different \ plans.

Plan\ A\ costs\ \$92\ per\ month\ for\ unlimited\ talk\ and\ text.\ Plan\ B\ costs \ $0.20\ per\ minute\ plus\ \$0.10\ per\ text\ message\ sent.You\  need \  to\   purchase \  a \  plan \  for\   your \  14-year-old \  sister.Your\  sister\  currently \ uses\  1,750 \ minutes\  and \ sends\  1,650 \ texts\  each \ month.(1) What\  is\   your \  sister's\   total\   cost\   under \  each\   of\   the\   two\   plans?

(2) Suppose\  your\  sister\  doubles\  her\  monthly\  usage \ to\  3,500\  minutes \ and\  sends\  3,300 \ texts.What \ is \  your  \ sister's \  total \  cost \  under \  each \  of  \ the \  two \  plans?

Now, to find (1) total cost for each of the two plans. (2) Total cost under each of the two plans, if sister doubles her monthly usage to 3,500 minutes and sends 3,300 texts.

<h3>(1) </h3>

As, the Plan A is for unlimited talk and text

Cost of the Plan A = $92.

<u><em>Now, to find the cost under Plan B:</em></u>

According to question:

Rate of call per minute is $0.20 and per text is $0.10.

Calls she uses currently is 1,750 minutes and text 1,650.

<u><em>So, to get the cost of Plan B:</em></u>

0.20\times 1750+0.10\times 1650

=350+165

=515.

Thus, Plan B costs $515.

<h3>(2)</h3>

<u><em>Now, to get the total cost as, sister doubles her monthly usage to 3,500 minutes and sends 3,300 texts.</em></u>

As, the Plan A is same in both cases and is for unlimited text and calls.

So, cost of Plan A = $92.

As, the monthly usage is double.

Calls in minutes are 3,500.

Texts are 3,300.

<u><em>Now, to get the total cost under Plan B:</em></u>

0.20\times 3500+0.10\times 3300

=700+330

=1030.

Hence, the cost of Plan B = $1,030.

Therefore, (1) The total cost under Plan A is $92 and the total cost under Plan B is $515.

(2) The total cost under Plan A is $92 and the total cost under Plan B is $1,030.

7 0
3 years ago
Matrix a is a 6 × 5 matrix. which order of matrix can be multiplied by matrix a to create matrix ab?
mezya [45]

Order (B) 5 × 6 of the matrix can be multiplied by matrix a to create matrix ab.

<h3>What is a matrix?</h3>
  • A matrix is a rectangular array or table of numbers, symbols, or expressions that are organized in rows and columns to represent a mathematical object or an attribute of such an object in mathematics.
  • For instance, consider a matrix with two rows and three columns.

To find the order of matrix:

  • We must first check the dimension of two matrices, say matrix A by matrix B, before we may multiply them.
  • Multiplication is achievable if the number of columns in the first matrix, A, equals the number of rows in the second matrix.
  • Dimension is assigned to the provided matrix: 6 × 5
  • This means the given matrix contains six rows and five columns.
  • As a result, the second matrix MUST have 5 rows in order for multiplication to be POSSIBLE.
  • The only matrix with 5 rows among the above alternatives is the matrix with dimension (B) 5 × 6.

To prove:

  • In other words, the inner products of the dimensions should be equal.
  • That is; (a × b)(b × a) is possible but (a ×b)(c × b) is impossible.
  • The dimensions of the matrix are given by, row × column.

Therefore, order (B) 5 × 6 of the matrix can be multiplied by matrix a to create matrix ab.

Know more about matrix here:

brainly.com/question/24079385

#SPJ4

7 0
2 years ago
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